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Genrish500 [490]
3 years ago
5

Which statement accurately describes what happens when water vapor condenses into dew in terms of energy?

Physics
2 answers:
son4ous [18]3 years ago
6 0

The correct explanation for the process of formation of dew from the water vapour is The water releases energy which causes the water molecules to have less kinetic and potential energy, changing their configuration from gas to liquid.

vapour is a gaseous form, while dew is a liquid state of matter therefore it's clear that vapour has to release energy to come in the liquid state, and in this process vapour, water molecules lose their kinetic and potential energy.

Nataly [62]3 years ago
4 0

the correct answer is B.

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What is the resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm2?​
nadya68 [22]

The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)

The relation of resistance with length and thickness is given by ;

\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{5.6 \times 10^{-8}\times 2}{0.15 \times 10^{-6}} \\\\ R=0.74 \ ohm

Hence, the resistance of tungsten wire will be 0.74 ohm.

To learn more about the resistance, refer to the link;

brainly.com/question/20708652

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2 years ago
Linear expansivity?<br>​
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3 years ago
Describe the energy changes in mass-spring system that is oscilating horizontally.​
SashulF [63]

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Explanation:

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4 0
3 years ago
G=fr²/m,m²
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Do you have a question to ask ?
6 0
4 years ago
An 8.00-kg point mass and a 12.0-kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be
9966 [12]

Answer:

Acceleration of the particle is 4.45 m/s² and acceleration direction is towards the 8 kg point mass.  

Explanation:

Let m₁ be 8 kg point mass and m₂ be 12 kg point mass and take direction along m₁ mass as positive x-axis. The separation between twp point masses is 50 cm. According to the problem, a particle of mass m is held between the two point masses m₁ and m₂.

Distance between m₁ and m, r₁ = 20 cm = 0.2 m

Distance between m₂ and m, r₂ = (50 - 20) cm =30 cm = 0.3 m

The particle of mass m experiences an attractive gravitational force due to both the point masses. Thus, the net force on the particle of mass m is :

F = F₁ + F₂

F₁ is acting along the positive x axis and F₂ is acting along the negative x axis.

F = \frac{Gm_{1}m }{r_{1} ^{2} } - \frac{Gm_{2}m }{r_{2} ^{2} }

Substitute the values of G, m₁, m₂, r₁ and r₂ in the above equation.

F = \frac{6.67\times10^{-11} \times8m }{0.2 ^{2} } - \frac{6.67\times10^{-11}\times12m }{0.3^{2} }

F = 4.45m N/kg

Acceleration of the particle = \frac{F}{m} = 4.45 m/s²

The direction of acceleration of the particle is towards the 8 kg point mass.

8 0
4 years ago
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