All categories

3 years ago

Use the substitution method to solve the system of equations. Choose the correct ordered pair.

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Answer:

A(2,5)

Step-by-step explanation:

x=2 and y=5

2y+4x=18

2y-3x=4

2(5) + 4(2) = 18

10+8=18

2(5)-3(2)=4

10-6=4

Tatiana [17]3 years ago

4 0

The answer should be A(2,5)

You might be interested in

Bacteria can multiply at an alarming rate when each bacteria splits into two new cells, thus doubling. If we start with only one

Elan Coil [88]

Answer:

2^24 = 16,777,216 bacterias.

Step-by-step explanation:

So we start with 1 bacteria

after 1 hours: 2*1 = 2

after 2 hours: 2*2 = 2^2 = 4

after 3 hours: 2*2^2 = 2^3

after n hours: 2^n

Since one day has 24 hours we have n = 24 and total number of bacteria will

be: 2^24 = 16,777,216 bacterias.

5 0

3 years ago

Consider a sequence given by the formula f(n)=3n-1 starting with n=1. Generate the first 5 terms of the sequence

Rufina [12.5K]

Answer:

The first 5 terms are 2, 5, 8, 11, 14.

Step-by-step explanation:

You use the formula to find out each term.
f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
Now to find each term:

n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14

So the first 5 terms are 2,5,8,11,14

5 0

3 years ago

What is the value of a in the equation 3+b=54 when b = 9

Fed [463]

Answer:

3a + b = 54

3a + 9 = 54

3a = 54 - 9

3a = 45

3a / 3 = 45 / 3

a = 15

5 0

3 years ago

In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th

11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

Probability that the students passed the second exam = P(S) = 0.72

Probability that the students passed both exams = $P(F \bigcap S)$ = 0.58