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3 years ago

After completing an experiment, all chemical wastes should be

Physics

1 answer:

WITCHER [35]3 years ago

6 0

Answer:

The correct answer is

C. disposed of according to your instructor’s directions

Explanation:

The question is not complete here is the complete one with options to choose from

After completing an experiment, all chemical wastes should be

A. taken home

B. dumped in the sink

C. disposed of according to your instructor’s directions

D. left at your lab station for the next class

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Streams of electrically charged particles flowing at high speeds from the sun make up the

pshichka [43]

That's the so-called 'solar wind'.

5 0

3 years ago

Help me mister brainly.

lesya [120]

Weight=585N

$\\ \rm\hookrightarrow mg=585\implies m=585/10=58.5kg$

Weight on moon is one sixth of earth

Weight on moon=58.5/6=9.75kg

$\\ \rm\hookrightarrow W=22.5(10)=225N$

Gravitational field=235.2-225=9.8N

$\\ \rm\hookrightarrow F=ma$

$\\ \rm\hookrightarrow m=F/a$

$\\ \rm\hookrightarrow m=970/4.4$

$\\ \rm\hookrightarrow m=220.4kg$

It is the centre of earth where g is 0

$\\ \rm\hookrightarrow F_{net}=240-120=120N$

8 0

2 years ago

A 6500 kg satellite orbits a planet. If its distance to the center of the planet is 9e6 m and its speed is 6.7e3 m/s, what is th

Ira Lisetskai [31]

Answer:

the gravitational force between the satellite and the planet is 32.4 * 10³N

Explanation:

It is given that,

Mass of the satellite, m = 6500 kg

Speed of the satellite, v = 6.7 × 10³ m/s

distance to the center of the planet = 9 × 10⁶m

Let F is the magnitude of the gravitational force exerted on the satellite by the planet. The centripetal force is equal to the gravitational force. It is equal to :

$F = \frac{mv^2}{R}$

$F = \frac{6500 \times (6.7 * 10^3)}{9 * 10^6}$

= 32.4 * 10³N

the gravitational force between the satellite and the planet is 32.4 * 10³N

3 0

3 years ago

Read 2 more answers

Se lanza verticalmente hacia arriba un cuerpo que para por un punto A con una rapidez de 54 m/s y por otro punto B situado mas a

Brut [27]

1) The time taken is 3.06 s

2) The distance between the two points is 119.4 m

Explanation:

The motion of the object is a free fall motion, so it is a uniformly accelerated motion with constant acceleration $a=g=-9.8 m/s^2$ towards the ground. So, we can solve the problem by using the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

In this problem we have

u = 54 m/s is the initial velocity (at point A)

v = 24 m/s is the final velocity (at point B)

$a=-9.8 m/s^2$ is the acceleration (negative since it is downward)

Solving for t,

$t=\frac{v-u}{a}=\frac{24-54}{-9.8}=3.06 s$

For this part of the problem, we can use another suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

In this problem we have

u = 54 m/s

v = 24 m/s

$a=-9.8 m/s^2$

Solving for s, we find the distance between point A and point B, which is the distance covered by the object:

$s=\frac{v^2-u^2}{2a}=\frac{24^2-54^2}{2(-9.8)}=119.4 m$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0

4 years ago

Mickey, a daredevil mouse of mass 0.0227 kg,0.0227 kg, is attempting to become the world's first "mouse cannonball." He is loade

Viefleur [7K]

Answer:

1.65 m

Explanation:

Energy from spring, $E_{s}$ is given by

$E_{s}=0.5kx^{2}$ where k is spring constant and x is the compression distance

$E_{s}=0.5*51.1*0.129^{2}= 0.425178$

$E_{s}=0.425 J$

Kinetic energy, KE at the highest point is given by

$KE=0.5mv^{2}$ where m is mass and v is velocity

KE=0.5*0.0227*2.27= 0.058485 J

Potential energy, PE of spring is given by

PE=mgh where g is gravitational constant and h is maximum height reached by the mouse

PE=0.0227*9.81= 0.222687h

According to the principle of conservation of energy, the potential energy of the compressed spring is equal to the potential and kinetic energy of the mouse at the maximum high point.

$E_{s}=PE+KE$

0.425=0.222687h+0.058485

h=(0.425-0.058485)/ 0.222687=1.646671 m

h=1.65 m

7 0

3 years ago