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3 years ago

Would time travel ever be possible? If so how and through what extensive process would it might be possible.

Physics

2 answers:

crimeas [40]3 years ago

6 0

Answer:

It is and is not possible and if it is there are many factors to it at many dire consequences that come if we somehow interact with the people from the past

makkiz [27]3 years ago

4 0

Answer:

There are two ways we may, one day, be able to time travel forwards.

You may have heard of Cryogenics. This is when someone who’s died is frozen instead of being buried or cremated. The theory is they can be “woken up” in the future when we have the technology to bring them back to life. Or a machine or device could be developed so that some people age more slowly than others around them. This way they’d live longer and see a future beyond the average person’s life span.

Another very different way of travelling into the future is more like what you’d see in science fiction. This is might involve travelling in a rocket or spaceship at a very high speed, close to the speed of light. “We can’t establish equality with the speed of light but it is possible, in theory, to travel nearly as fast as the speed of light,” adds Dr Steane.

So imagine you’re in a spaceship travelling very fast away from the Earth and you stay in orbit for a year. You would age at the same rate as if you were still on the Earth, by a year, but when you returned, the earth may have aged hundreds of years. “This is way beyond the technology we have at the moment,” he says. “But... in theory, it is possible.”

Explanation:

Hope this helped!

You might be interested in

How are calculation for velocity and speed different

BARSIC [14]

Only velocity uses direction of travel in its calculations.

5 0

3 years ago

A solar cell, 3.0 cm square, has an output of 350 mA at 0.80 V when exposed to full sunlight. A solar panel that delivers close

Vesna [10]

Answer:

You will need 450 cells (3 cm each) to meet the voltage/current requirement.

The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.

The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.

Explanation:

To meet the voltage:

120 [v] required voltage

0.8 [v] voltage of each cell

$\frac{120}{0.8} =150[v]\\$

So we need 150 cells in series for the voltage.

To meet the current

1.0 [A] Required current

350[mA]=0.35[A] cell current

1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.

See the attached figure

8 0

3 years ago

Creativity is always discouraged in scientific endeavors.

shepuryov [24]

Absolutely false!! Creativity, curiosity encouraged in Scientific endeavors. Science is all about exploring knowledge, it just promotes intelligency!

In Short, Your Answer would be "False"

Hope this helps!

3 0

3 years ago

Read 2 more answers

A single insulated duct flow experiment using air operating at steady-state is performed in a lab. One measurement location (Sta

weqwewe [10]

Answer:

a) -0.0934 kJ/kg. K

b) The direction of flow is from right to left.

Explanation:

A free flow diagram of the horizontal insulated duct is as shown below.

NOW,

Let assume that the direction of flow is from left to right and consider the following relation for the entropy rate balance equation for a control volume as:

$\frac{\sigma_{cv}}{m}= (s_2-s_1) \geq 0 \ \ \ -------> \ \ \ 1$

Now; if the value for this relation is greater than zero; then we conclude that our assumption is correct.

If the value is less than zero; then we conclude that the assumption is wrong.

Then, the flow is said to be in the opposite direction

Formula for the change in specific entropy can be calculated as:

$s_2-s_1 = s^0(T_2) - s^0(T_1)-R \ In ( \frac{P_2}{P-1}) \ \ \ -------> \ \ \ 2$

where;

$s_1, s_2 , s^0(T_2), s^0(T1)$ are specific entropies

R = universal gas constant

$P_1$ = pressure at location 1

$P_2$ = pressure at location 2

We obtain the specific properties of air at temperature at $T_1$ = (67°C + 273)K = 340 K from the table A-22 ( Ideal gas properties of air)

$s^0(T1)$ = 1.8279 kJ/kg.K

We also obtain the specific properties of air at temperature $T_2$ = 22°C + 273) K = 295 K

From the table A- 22

$s^0(T_2)$ = 1.68515 kJ/kg . K

R = $\frac{8.314 kJ}{28.97 kg.K}$

$P_1 =$ 0.95 bar

$P_2 =$ 0.8 bar

Now replacing our values into equation (2) from above; we have;

$s_2-s_1 = s^0(T_2) -s^0(T_1)-R \ In (\frac{P_2}{P_1} )$

$s_2-s_1 = 1.68515 -1.8279-\frac{8.314}{28.97} \ In (\frac{0.8}{0.95} )$

$s_2-s_1 = 1.68515 -1.8279+ 0.0493$

$s_2-s_1 =-0.0934 \ kJ/kg.K$

Equating our result to equation (1)

$s_2-s_1 \geq 0\\-0.0934 \leq 0$

Therefore , our assumption is wrong and the direction of flow is said to be from right to left.

We therefore conclude that the direction of flow is from right to left.

3 0

3 years ago

An experiment is designed to investigate the relation between the pressure and temperature in a tank that has a constant volume

viva [34]

Answer:

3rd order polynomial

Explanation:

Given that the increase in the order of the polynomial the error between the curve fit and measured data will decreases hence :

The polynomial order that is best to use is the 3rd order polynomial, this is because using a 3rd order polynomial will produce a less variance and a low Bias

4 0

3 years ago