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mylen [45]
3 years ago
9

What are the three ways acceleration can occur

Physics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

Change in velocity, change in direction, change in both velocity and direction

Explanation:

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Which pair of elements is most similar?<br> Na and CI<br> Li and Ne<br> Co and<br> Ne and Ar
UkoKoshka [18]

Answer:

If I remembered correctly the answer would be Ne and Ar(Neon and Argon

7 0
3 years ago
The amplitude of a wave<br> determines the volume of a<br> sound.<br> True<br> O False
Vikki [24]
True the amplitude of a wave determines the volume of a sound
6 0
2 years ago
Sunspots appear dark because they are cooler than the surrounding solar surface. True or false
DiKsa [7]

Answer:

False, Sunspots appear dark (in visible light) due to their low temperature(cooler) than rest of the sun

Explanation:

Sunspots appear dark because they are much cooler( have low temperature than the rest of the surface contained by Sun. As they appear dark, but still they have very temperature that's why so hot. Sunspots have temperatures ranges  3,500 Celsius (3773 kelvin) and the surrounding surface of the sun has a temperature much higher of about 5,500 Celsius(5773 Kelvin). Even if we see a sunspot alone in space,  it will glow so brightly.

Learn more about sunspots :

brainly.com/question/27774496

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6 0
2 years ago
How do we know that pulsars must be neutron stars?
slavikrds [6]

Answer:

funny

Explanation:

3 0
3 years ago
A nonconducting container filled with 25 kg of water at 23°C is fitted with a stirrer, which is made to turn by gravity acting o
Paul [167]

Explanation:

Given that,

Weight of water = 25 kg

Temperature = 23°C

Weight of mass = 32 kg

Distance = 5 m

(a). We need to calculate the amount of work done on the water

Using formula of work done

W=mgh

W=32\times9.8\times5

W=1568\ J

The amount of work done on the water is 1568 J.

(b). We need to calculate the internal-energy change of the water

Using formula of internal energy

The change in internal energy of the water equal to the amount of the  work done on the water.

\Delta U=W

\Delta U=1568\ J

The  change in internal energy is 1568 J.

(c). We need to calculate the final temperature of the water

Using formula of the change internal energy

\Delta U=mc_{p}\Delta T

\Delta U=mc_{p}(T_{2}-T_{1})

T_{2}=T_{1}+\dfrac{\Delta U}{mc_{p}}

T_{2}=23+\dfrac{1568}{25\times4.18\times10^{3}}

T_{2}=23.01^{\circ}\ C

The final temperature of the water is 23.01°C.

(d). The amount of heat removed from the water to return it to it initial temperature is the change in internal energy.

The amount of heat is 1568 J.

Hence, This is the required solution.

6 0
3 years ago
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