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SSSSS [86.1K]
3 years ago
5

For the reaction SO3 + H2O + H2SO4, how many grams of sulfuric acid can be

Chemistry
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

Mass = 544 g

Explanation:

Given data:

Mass of sulfuric acid formed = ?

Mass of water react = 100.0 g

Solution:

Chemical equation:

SO₃ + H₂O     →     H₂SO₄

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 100 g/ 18 g/mol

Number of moles = 5.5 mol

Now we will compare the moles of water and H₂SO₄.

                  H₂O       :         H₂SO₄

                     1          :            1

                 5.56       :           5.56

Mass of H₂SO₄:

Mass = number of moles × molar mass

Mass = 5.56 mol × 98.0 g/mol

Mass = 544 g

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how do i word a formal letter to a teacher saying i didn't pay attention during the science lessons and i now have no idea what
Allushta [10]

Explanation:

Hello mr/mrs (name) I unfortunately couldn't pay attention to the class due to some issues I had therefore I don't know what we are doing in class

OR

Hello mr/mrs (name) I could understand what we were doing in class I would like it if you could break it down more or explain better to me

OR just say something it had something to do with your internet such as

Hello mr/mrs (name) I didn't understand what you were saying during our class due to some of my internet issues I was have throughout the day. I hope you can explain what we did during the class.

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8 0
3 years ago
The fire department needs information on friction losses occurring between a water main and an open fire hydrant. At maximum mai
lisov135 [29]

Explanation:

The given data is as follows.

      P_{1} = 85 psig,   P_{2} = P_{atm} = 15 psia

        Q = 1620 gpm,  d = 2.5 inch,     l = 8 ft = 2.4384 m

According to Darey-Weisbach equation,

                        h_{l} = \frac{4fl \nu^{2}}{2gD}  ......... (1)

Value of 'f' will be decided on the basis of Reynold number.

As, it is known that R_{l} = \frac{\rho \nu d}{\mu}

where,  \mu_{water} = 10^{-3} kg/ms

As it is known that 1 gpm = \frac{1}{3.67} m^{3}/hr

So,  1 m^{3}/hr = 3.67 gpm

Therefore,   Q = 1620 \times \frac{1}{3.67}

                        = 441.4168 m^{3}/hr

                         = 0.1226 m^{3}/s

In, 1 inch = 2.54 cm = 0.0254 m

Therefore, d = 2.5 \times 0.0254 = 0.0635 m

                V = \frac{Q}{\frac{\pi}{4}d^{2}}

                    = \frac{0.1226}{0.785 \times (0.0635)^{2}}

                    = 38.73 m/s

Hence, we will calculate Reynold number as follows.

             R_{l} = \frac{1000 \times 38.73 \times 0.0635}{10^{-3}}

                             = 2459355

As R_{l} > 2000 then, it means that flow is turbulent.

As, f = 0.079 R^{-0.25}_{l}

        = 0.001994

Putting all the values into equation (1) formula as follows.    

                          h_{l} = \frac{4fl \nu^{2}}{2gD}

                                     = \frac{4 \times 0.001994 \times 2.4384 \times (38.73)^{2}}{2 \times 9.81 \times 0.0635}

                                      = 1.04069 \times 10^{5} m

Thus, we can conclude that friction loss from the main to the discharge point is 1.04069 \times 10^{5} m.

4 0
3 years ago
When there are 0.0814 moles of hockey pucks how many hockey pucks are there?
Dovator [93]

Answer:

4.9 x 10²²hockey pucks

Explanation:

Given parameters:

Number of moles of hockey  = 0.0814moles

Unknown:

Number of pucks there = ?

Solution:

A mole of a substance is made up of Avogadro's number of particles.

Therefore;

       1 mole of hockey pucks will contain 6.02 x 10²³ hockey pucks

       0.0814 mole of hockey pucks will contain :

                              0.0814 x 6.02 x 10²³ = 4.9 x 10²²hockey pucks

8 0
3 years ago
Give the quantum numbers for the last electron in:
Blizzard [7]

Answer:

a) Gold: 5, 2, 2, -1/2

b) Magnesium : 3, 0, 0, -1/2

c) Iodine: 5, 1, 0, -1/2

d) Cadmium: 4, 2, 2, -1/2

Explanation:

To understand Chemistry in its true sense, it is necessary to know the way the electrons are arranged within the atom and also understand the how and why of the bond and reactivity. To do this, you must first know the how and why of the electronic structure. , this can be done with quantum numbers.

The quantum numbers are four and they help us to describe the place of the electrons in the vicinity of the nucleus.

8 0
3 years ago
What are some examples of rapid changes
SSSSS [86.1K]
1) color change - for example, when bleach is shot down by mistake, in colored clothing;

2) gas release - for example, when playing an effervescent tablet in water.

3) heat release - for example in combustion;

hope this helps!.
7 0
3 years ago
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