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qwelly [4]
3 years ago
11

Water is found in which of the following states at earth's surface?

Chemistry
2 answers:
MAXImum [283]3 years ago
8 0
B because those are the elements
snow_tiger [21]3 years ago
7 0

Answer:

Only liquid or Liquid, Gas, ane Solid.

Explanation:

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Please help me balance:<br>_NaNO3 + _PbO_ ➡️ Pb(NO3)2 + _Na2O
KengaRu [80]

Answer:

The balanced reaction is given by,

2NaN(O)3 + PbO ⇒ Pb(NO3)2 + Na2O

Explanation:

The reaction is as given.

Lets count the number of each elements in the reaction.

<em>In reactant side, number of sodium atoms are 1 , lead are 1, nitrogen are 1 and oxygen are 4.</em>

<em>in product side, number of sodium atoms are 2 , lead are 1 , nitrogen are 2 and oxygen are 7.</em>

<em>So we need to balance sodium and oxygen atoms in the reaction.</em>

<em>There is deficient of sodium and oxygen atoms on reactant side</em>.

Thus, multiply (NaNO3) by 2.

<em>Thus, sodium atoms become 2 , nitrogen 2 and oxygen 6. Total 7 oxygen atoms.</em>

Thus, the balanced reaction is,

2NaN(O)3 + PbO ⇒ Pb(NO3)2 + Na2O

7 0
2 years ago
Select the name of the element with a condensed ground-state electron configuration of [kr] 5s14d7.
Vilka [71]

elements have equal number of protons and neutrons

the condensed format is when the closest noble gas with the closest electron configuration is given, this closest noble gas atomic number should be lesser than the atoms atomic number

atomic number of Kr is 36

1 electron in 5s subshell and 7 electrons in 4d subshell.

there's a total of 36 + 1 + 7 = 44 electrons

atomic number of the atom is 44

element with atomic number 44 is Ruthenium - Ru

answer is Ru


7 0
2 years ago
Read 2 more answers
One example of an ionic compound is<br><br> F2 <br> CO2<br> HBr<br> MgCL2
allochka39001 [22]
MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
7 0
3 years ago
Read 2 more answers
How many atoms are there in 8.88 g Si?
Mariana [72]

Answer:

\boxed {\boxed {\sf 1.90 \times 10^{23} \ atoms \ Si}}

Explanation:

We are asked to find how many atoms are in 8.88 grams of silicon.

<h3>1. Grams to Moles </h3>

First, we convert grams to moles. We use the molar mass or the mass of 1 mole of a substance. These values are found on the Periodic Table as they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.

Look up silicon's molar mass.

  • Si:  28.085 g/mol

We will convert using dimensional analysis. Set up a conversion factor with the molar mass.

\frac { 28.085 \ g \  Si}{1 \ mol \ Si}

We are converting 8.88 grams of silicon to moles, so we multiply by this value.

8.88 \ g \ Si *\frac { 28.085 \ g \  Si}{1 \ mol \ Si}

Flip the fraction so the units of grams of silicon cancel.

8.88 \ g \ Si *\frac{1 \ mol \ Si} { 28.085 \ g \  Si}

8.88  *\frac{1 \ mol \ Si} { 28.085 }

\frac {8.88} { 28.085 } \ mol \ Si

0.316183015845 \ mol \ Si

<h3>2. Moles to Atoms </h3>

Next, we convert moles to atoms. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of silicon.

Set up another conversion factor.

\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}

Multiply by the number of moles we calculated.

0.316183015845\ mol \ Si *\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}

The units of moles of silicon cancel.

0.316183015845 * \frac {6.022 \times 10^{23} \ atoms \ Si}{1}

0.316183015845 * {{6.022 \times 10^{23} \ atoms \ Si}

1.90405412 \times 10^{23} \ atoms \ Si

<h3>3. Significant Figures</h3>

The original measurement of 8.88 grams has 3 significant figures, so our answer must have the same.

For the number we calculated, that is the hundredth place. The 4 in the thousandth place tells us to leave the 0 in the hundredth place.

1.90 \times 10^{23} \ atoms \ Si

<u>8.88 grams of silicon contains 1.90 ×10²³ atoms of silicon.</u>

6 0
3 years ago
Aerobic cellular respiration requires an adequate supply of​
Varvara68 [4.7K]

Answer:

oxygen ?

Explanation:

not sure but I think so

3 0
3 years ago
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