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krek1111 [17]
3 years ago
10

If 22.6 grams of an aqueous solution of zinc nitrate, Zn(NO3)2, contains 5.08 grams of zinc nitrate, what is the percentage by m

ass of zinc nitrate in the solution?
____% Zn(NO3)2
Chemistry
1 answer:
sesenic [268]3 years ago
5 0

Answer:

22.5%

Explanation:

To find percentage by mass, you divide the mass of the solute by the mass of the solvent.

5.08 g/22.6 g = 0.2248 = 22.5%

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