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krek1111 [17]
4 years ago
10

If 22.6 grams of an aqueous solution of zinc nitrate, Zn(NO3)2, contains 5.08 grams of zinc nitrate, what is the percentage by m

ass of zinc nitrate in the solution?
____% Zn(NO3)2
Chemistry
1 answer:
sesenic [268]4 years ago
5 0

Answer:

22.5%

Explanation:

To find percentage by mass, you divide the mass of the solute by the mass of the solvent.

5.08 g/22.6 g = 0.2248 = 22.5%

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

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