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3 years ago

How can parentheses be added to the following equation to make it true?

Mathematics

2 answers:

Lemur [1.5K]3 years ago

7 0

Step-by-step explanation:

Add parentheses around 1 + 1.

8 - 3 × 2 - (1 + 1) = 0

8 - 6 - 2 = 0

0 = 0

pantera1 [17]3 years ago

5 0

Answer: The answer is 0.

Step-by-step explanation: You'll need to add the parentheses around 1+1.

The solution:

$8-3*2-(1+1)$ 2. $8-6-2$ 3. $0$

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Tell whether x and y show direct variation.Explain your reasoning.If so, find k #3

WINSTONCH [101]

Answer:

x and y do not show direct variation.

Step-by-step explanation:

The formula for direct variation is

y = kx Divide each side by y

k = y/x

k should have the same value for every point except, of course, (0,0)

For the first point,

k = 2/(-1) = -2

For the third point,

k = 2/1 = 2

The values of k are different, so x and y <em>do not</em> show direct variation.

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4 years ago

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Find the slope of the line passing through each of the following pairs of points: A(−7, a) and B(c, d)

Mrrafil [7]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points A(-7, a) and B(c, d).

Substitute:

$m=\dfrac{d-a}{c-(-7)}=\dfrac{d-a}{c+7}$

Exception: c ≠ -7.

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4 years ago

The point (1,−1) satisfies the inequality 40x−22y≤50.

Natalka [10]

Không thảo mãn vì

44.1-22.(-1)=66

7 0

3 years ago

If you divide a number by a other number will it always be smaller?

ioda

No you can divide 0.5 by 0.25 and you will get 2

6 0

3 years ago

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A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

4 years ago