Well, what I would do is divide it into two shapes. Cut off the bottom part to make two separate quadrilaterals, and you'd have a square with sides of x. So the area would be x^2. Then, for the remaining piece (rectangle), add the x from the square bit to 5 for one side, and the other side would be x. So you'd have 5x * x, which equals 5x^2. Add the two separate area's together to get the total area, which would give you 6x^2. Hope that helped! :)
202 ft^2
The lateral area is the area of all the sides except the base. So you find the area of the triangles (16), then the left rectangle (80), then the right rectangle (90). Finally you add them together.
16+16+80+90=202
I think u would do 75-3=72. 72÷2=36. I think the answer would be 36 yards.
so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant
![\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx%7D%7B9%7D~~%2C~~%5Cstackrel%7By%7D%7B-3%7D%29%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Bhypotenuse%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B9%5E2%2B%28-3%29%5E2%7D%5Cimplies%20c%3D%5Csqrt%7B81%2B9%7D%5Cimplies%20c%3D%5Csqrt%7B90%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
Option D (4, -5)
Step-by-step explanation:
This question can be solved by various methods. I will be using the hit and trial method. I will plug in all the options in the both the given equations and see if they balance simultaneously.
Checking Option 1 by plugging (-4, -5) in the first equation:
-2(-4) + 6(-5) = -38 implies 8 - 30 = -38 (not true).
Checking Option 2 by plugging (-5, 4) in the first equation:
-2(-5) + 6(4) = -38 implies 10 + 24 = -38 (not true).
Checking Option 3 by plugging (1, -6) in the second equation:
3(1) - 4(-6) = 32 implies 3 + 24 = 32 (not true).
Since all the options except Option 4 have been ruled out, therefore, (4,-5) is the correct answer!!!
