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3 years ago

What are the solutions to the inequality (4x-3)(2x-1) greater than or equal to 0

Mathematics

2 answers:

Fynjy0 [20]3 years ago

6 0

Answer:

3/4 and 1/2

Step-by-step explanation:

(4x-3)(2x-1) ≥ 0

If the product of 2 numbers is zero, the one of the numbers must be equal to zero.

(4x-3)(2x-1) ≥ 0

(4x-3) ≥ 0 or (2x-1) ≥ 0

4x ≥ 0+3 2x ≥ 0+1

4x ≥ 3 2x ≥ 1

x ≥ 3/4 x ≥ 1/2

KengaRu [80]3 years ago

4 0

Answer:

Solutions are x ≥ 3/4 and x ≥ 1/2.

Step-by-step explanation:

In the given question an inequality has been given and we have to find out the solutions.

First we write down the inequality as

(4x-3)(2x-1) ≥ 0

From this inequality we can say that there are two solutions.

Therefore the factor 4x-3 ≥ 0 ⇒ 4x ≥ 3

⇒ x ≥ 3/4

Now 2x-1 ≥ 0

⇒ 2x ≥ 1

⇒ x ≥ 1/2

means this inequality has the two sets of the solutions.

One is all the positive numbers greater than equal to 3/4 and all the positive numbers greater than equal to 1/2.

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