When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1
<h3><u>Solution:</u></h3>
Given that when 6 is subtracted from the square of a number, the result is 5 times the number
To find: negative solution
Let "a" be the unknown number
Let us analyse the given sentence
square of a number = 
6 is subtracted from the square of a number = 
5 times the number = 
<em><u>So we can frame a equation as:</u></em>
6 is subtracted from the square of a number = 5 times the number

<em><u>Let us solve the above quadratic equation</u></em>
For a quadratic equation
where 

Here in this problem,

Substituting the values in above quadratic formula, we get

We have two solutions for "a"

<h3>a = 6 or a = -1</h3>
We have asked negative solution. So a = -1
Thus the negative solution is -1