Find midpoint of segment.
(-1,1), (7,-5)

Find slope of line which passes through (-1,1) and (7,-5).

The slope of perpendicular line is negative reciprocal value of m.

Write quation of line which slope is

and passes throug the point (3,-2).
Just draw a graph and plot them on the graph then count how many squares (in short) there is between them.
1) f(x)=2x
when x=3 then f(x) =3×2=<em><u>6</u></em>
when x=4 then f(x)=4×2=<em><u>8</u></em>
2)At y=35(no. of mangoes),x corresponds to y=60(amount)
so$<em><u>6</u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>he</u></em><em><u> </u></em><em><u>need</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>spend</u></em><em><u>!</u></em>
3) f(x)= x+2
for x=1, f(x)=1+2=<em><u>3</u></em>
for x=2,f(x)=2+2=<em><u>4</u></em>
✌️:)
Problem 1
Domain = {-1, -3, 2, 1}
Range = {5, 0, 2}
The domain is the set of possible inputs and the range is the set of possible outputs. This is a function because each input goes to exactly one output.
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Problem 2
This is a function as well. We do not have any input going to multiple outputs.
Domain = {-2, -3, 5}
Range = {6, 7, 8}
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Problem 3
This is not a function. The input -4 goes to more than one output (outputs 3 and -1 at the same time)
Domain = {-4, -2, 0}
Range = {3, -1, -2, 4}
3(x-5)-4(x+3)
Multiply the first bracket by 3
(3)(x)=3x
(3)(-5)=-15
(-4)(x)=-4x
(-4)(3)=-12
3x-15-4x-12
3x-4x-15-12 ( combine like terms)
Answer: -x-27