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Basile [38]
3 years ago
9

Let f(x)=2x-6. Solve f^-1(x) when x=2 -5 4 -2 7

Mathematics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

4.

Step-by-step explanation:

f^-1(x) is the inverse of f(x). That means that f(x) = 2x - 6 becomes...

x = 2y - 6

2y - 6 = x

2y = x + 6

y = 1/2x + 3.

When x = 2...

y = 1/2(2) + 3

= 1 + 3

= 4.

Hope this helps!

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m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}

The slope of perpendicular line is negative reciprocal value of m.
m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}

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3 years ago
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salantis [7]
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7 0
2 years ago
Can anyone help me with this page i can’t find the answers
Dvinal [7]

1) f(x)=2x

when x=3 then f(x) =3×2=<em><u>6</u></em>

when x=4 then f(x)=4×2=<em><u>8</u></em>

2)At y=35(no. of mangoes),x corresponds to y=60(amount)

so$<em><u>6</u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>he</u></em><em><u> </u></em><em><u>need</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>spend</u></em><em><u>!</u></em>

3) f(x)= x+2

for x=1, f(x)=1+2=<em><u>3</u></em>

for x=2,f(x)=2+2=<em><u>4</u></em>

✌️:)

8 0
2 years ago
Can anybody tell me the answers to number 1, 2 &amp; 3 ???!!!!
Novay_Z [31]

Problem 1

Domain = {-1, -3, 2, 1}

Range = {5, 0, 2}

The domain is the set of possible inputs and the range is the set of possible outputs. This is a function because each input goes to exactly one output.

========================================

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This is a function as well. We do not have any input going to multiple outputs.

Domain = {-2, -3, 5}

Range = {6, 7, 8}

========================================

Problem 3

This is not a function. The input -4 goes to more than one output (outputs 3 and -1 at the same time)

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