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3 years ago

If 4 notebooks and 3 packages of pens cost $7.43 and

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

Answer:

i believe its one of these!

A. $0.89 B.$0.79 C. $1.29

Step-by-step explanation:

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A quality-control engineer samples 100 items manufactured by a certain process, and finds that 15 of them are defective. True or

goldenfox [79]

Answer: b) The probability that an item produced by this process is defective is likely to be close to 0.15, but not exactly equal to 0.15.

Step-by-step explanation:

Given that:

Number of samples = 100

Number of defective samples = 15

Proportion =number defective samples / total samples

P = 15 / 100 = 0.15

Hence, the probability that an item produces is defective is 0.15.

However, due to sampling Variations, the probability will be corrected for these variations. Hence, probability that an item produced by this process is defective is likely to be close to 0.15, but not exactly equal to 0.15.

5 0

2 years ago

Laila reads 36 pages in 4 hours which expression can be used to find the number of pages she reads per hour

djverab [1.8K]

Answer:

Step-by-step explanation:

36 pages divided by 4

6 0

2 years ago

Please help I don't get this one

Semenov [28]

Its A you just have to count the lines and say the numbers 1-4

7 0

3 years ago

HELP PLS

Snezhnost [94]

Answer:

a loss of 72.47

Step-by-step explanation:

I got this answer right on my test

6 0

3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

3 years ago