Ask question

Ask question

All categories

3 years ago

5

To rent a certain meeting room, a college charges a reservation fee of $36 and an additional fee of $8.80 per hour. The history

club wants to spend less than
$106.40 on renting the meeting room
What are the possible amounts of time for which they could rent the meeting room?
Use t for the number of hours the meeting room is rented, and solve your inequality for t.

1 answer:

just olya [345]3 years ago

3 0

Answer:

the maximum hours that they can rent it for is 8

Step-by-step explanation:

36 + 8.8t < 106.4

8.8t < 70.4

t < 8

You might be interested in

What is the slope of the line passing through the points (0, 4) and (-8, -1)?

Bas_tet [7]

Answer:

0.625

Step-by-step explanation:

Given the points :

(0, 4) and (-8, -1)

x1 = 0 ; y1 = 4

x2 = - 8 ; y2 = - 1

Slope, m = rise / run

Rise = y2 - y1 = - 1 - 4 = - 5

Rise = x2 - x1 = - 8 - 0 = - 8

The slope, m = - 5 / - 8

Slope, m = 0.625

7 0

3 years ago

A runner finished a total of 1,500 kilometers in races before retiring . She finished thirty-two 15-kilometer races . The rest o

Sindrei [870]

Answer:

32*15 = 480

1500-480 = 1020

1020/10

102 races

Step-by-step explanation:

5 0

2 years ago

Complete the work to find the dimensions of the rectangle. x(x – 3) = 10 x2 – 3x = 10 x2 – 3x – 10 = 10 – 10 (x + 2)(x – 5) = 0

Norma-Jean [14]

Answer:

$Length =5$

$Width = 2$

Step-by-step explanation:

Given

$Length =x$

$Width = x -3$

$Area = 10$

$x(x-3) =10$

See comment for missing part of the question

Required

Complete the expression to determine the dimension of a rectangle

We have:

$x(x-3) =10$

Open bracket

$x^2 -3x = 10$

Equate to 0

$x^2 -3x - 10 =0$

Expand

$x^2 + 2x - 5x - 10 = 0$

Factorize

$x(x + 2) - 5(x + 2) = 0$

Factor out x + 2

$(x - 5)(x + 2) = 0$

Solve for x

$x - 5 = 0$ or $x + 2 = 0$

$x = 5$ or $x = -2$

The value of x cannot be negative

So:

$x = 5$

Recall that:

$Length = x$

$Width = x - 3$

So:

$Length =5$

$Width = 2$ ---- i.e. 5 - 3

6 0

2 years ago

Please help! A-level maths.

astra-53 [7]

$x+y=k\implies y=k-x$

Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

We're told the line $x+y=k$ intersects $C$ twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.

So $7\le k$ ; in set notation,

$\{k\mid 7\le k$

4 0

3 years ago

Translate from words into math notation:<br><br> The sum of 2 and 4 gives 6

shepuryov [24]

Answer:

X+2+4=6

Step-by-step explanation:

I HOPE IT HELP.......

6 0

2 years ago