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kodGreya [7K]
3 years ago
12

can you please show me how to do this so I can teach it to my boys? They need to Express percents as fractions or mixed numbers,

and to express each percent as a decimal.​

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

for question 9 is not that hard

Step-by-step explanation:

take the 8% and just get rid of the percentage away and add a decimal like this 8. then you move it back which should make this 0.8 hope this helps for that section

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Which number is greater 17×10^8 4×10^8
Sunny_sXe [5.5K]

Answer:

17×10^8 is greater

Step-by-step explanation:

The expontent comes first which gives you

1000000000 then you multiply that with 17 to get

1700000000

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3 years ago
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(9x2 + 8x) – (2x2 + 3x)
Arte-miy333 [17]

Answer: 14+5x

Step-by-step explanation:

(18+8x) - (4+3x)

18+8x-4-3x

14+5x

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4 years ago
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The half-life of cesium-137 is 30 years. Suppose we have a 180-mg sample. (a) Find the mass that remains after t years. (b) How
DedPeter [7]

Answer:

a) Q(t) = 180e^{-0.023t}

b) 11.4mg of cesium-137 remains after 120 years.

c) 225.8 years.

Step-by-step explanation:

The following equation is used to calculate the amount of cesium-137:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t years, Q(0) is the initial amount, and r is the rate at which the amount decreses.

(a) Find the mass that remains after t years.

The half-life of cesium-137 is 30 years.

This means that Q(30) = 0.5Q(0). We apply this information to the equation to find the value of r.

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-30r}

e^{-30r} = 0.5

Applying ln to both sides of the equality.

\ln{e^{-30r}} = \ln{0.5}

-30r = \ln{0.5}

r = \frac{\ln{0.5}}{-30}

r = 0.023

So

Q(t) = Q(0)e^{-0.023t}

180-mg sample, so Q(0) = 180

Q(t) = 180e^{-0.023t}

(b) How much of the sample remains after 120 years?

This is Q(120).

Q(t) = 180e^{-0.023t}

Q(120) = 180e^{-0.023*120}

Q(120) = 11.4

11.4mg of cesium-137 remains after 120 years.

(c) After how long will only 1 mg remain?

This is t when Q(t) = 1. So

Q(t) = 180e^{-0.023t}

1 = 180e^{-0.023t}

e^{-0.023t} = \frac{1}{180}

e^{-0.023t} = 0.00556

Applying ln to both sides

\ln{e^{-0.023t}} = \ln{0.00556}

-0.023t = \ln{0.00556}

t = \frac{\ln{0.00556}}{-0.023}

t = 225.8

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8 0
3 years ago
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kogti [31]

Answer:

4.29 for 12 oz

Step-by-step explanation:

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7 0
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PLEASE HELP ASAP!!!!!!!!!
enot [183]

Answer:

Below in bold.

Step-by-step explanation:

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= π * 7

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= 38.48 cm^2 to nearest hundredth.

8 0
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