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soldi70 [24.7K]
3 years ago
10

The length of a rectangular swimming pool is exactly three times as long

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

59m

Step-by-step explanation:

Length= 3 × ( width)

But perimeter= 2width + 2 Lenght= 472

Let length= X

Width= Y

X= 3Y.........eqn(1)

2X + 2Y= 472........eqn(2)

Substitute X= 3Y in eqn(2)

2(3Y) + 2Y = 472

6Y + 2Y= 472

8Y= 472

Y= 59 m

Hence, the width of the pool is 59 m

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8_murik_8 [283]

Answer:

36

Step-by-step explanation:

180-144=36

7 0
3 years ago
His college Jason can take a maximum of 21 hours each semester between elective classes and core classes each elective class cos
iogann1982 [59]

Answer:

  • D. e + c ≤ 21, 225e + 275c ≤ 6000

Step-by-step explanation:

Maximum of 21 hours each semester between elective classes and core classes, the required inequality is:

  • e + c ≤ 21

Each elective class cost $225 per semester hour and each core class costs $275, the sum is 225e + 275c.

He cannot spend more than $6,000, the required inequality is:

  • 225e + 275c ≤ 6000

Correct option is D

5 0
3 years ago
a bag contains 8 red balls and 6 green balls. michelle randomly draws 3 balls from the bag. she does not replace the balls after
earnstyle [38]

Answer:

Red balls 2/14

Green balls 1/14

Step-by-step explanation:

I hope that helped.

6 0
3 years ago
HELP ASAPPP 10 POINTS
serious [3.7K]
The one on the top should be a right triangle and the bottom one is not
6 0
3 years ago
Find 3 consecutive integers such that twice the first, plus three times the second, plus four times the third is 20. Please show
Neporo4naja [7]
Since the integers are consecutive, you could call them 'x', x+1,and x+2.
Or you could all them  x-1, 'x', and x+1.
Or you could call them  x-2, x-1, and 'x'.
It's up to you.  Each of those sets describes 3 consecutive numbers.

Most people will call them 'x', x+1, and x+2, so let's do that.

Now just go through the question and make the quantities it talks about:

"twice the first" . . . . 2(x)
"three times the second" . . . . 3(x+1)
"four times the third" . . . . . 4(x+2)

and finally, it says that the sum of those things is 20.
This should not be a major problem.

2x + 3(x+1) + 4(x+2) = 20

You can probably handle it from here, but I'll continue anyway.
The next thing to do is take out all the parentheses:
3(x+1) = 3x + 3
4(x+2) = 4x + 8
Now add up the whole thing again, but without parentheses:

2x + 3x + 3 + 4x + 8 = 20

Gather all the x's together, and all the naked numbers together:

(2x + 3x + 4x) + (3 + 8) = 20

Addum up:   9x + 11 = 20

Subtract 11 from each side:   9x = 9

Divide each side by  9 :     x = 1

The first integer = x . . . . . . . <em>1</em>
The second integer = x+1 . .<em> . 2</em>
The third integer = x+2 . . . . .<em> 3 </em>

<u>Check:</u>

"twice the first" . . . . . . . . . . 2(1) = 2
"three times the second". . . 3(2) = 6
"four times the third" . . . . . . 4(3) = 12

Addum up:  2 + 6 + 12 = 20 just like the question said.      yay!



4 0
3 years ago
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