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soldi70 [24.7K]
3 years ago
10

The length of a rectangular swimming pool is exactly three times as long

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

59m

Step-by-step explanation:

Length= 3 × ( width)

But perimeter= 2width + 2 Lenght= 472

Let length= X

Width= Y

X= 3Y.........eqn(1)

2X + 2Y= 472........eqn(2)

Substitute X= 3Y in eqn(2)

2(3Y) + 2Y = 472

6Y + 2Y= 472

8Y= 472

Y= 59 m

Hence, the width of the pool is 59 m

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Answer:

Step-by-step explanation:

Hello!

The objective of the study is to determine whether the magnets are effective in treating pain. For these two independent groups of individuals with equal affections were randomly sampled, one was treated with magnets and the other group of individuals, call it control group, was treated with a placebo treatment.

The information for both samples is:

X₁: pain measurement using a visual analog scale after the individual received magnet treatments.

X₁~N(μ₁;σ₁²)

n₁= 20

X[bar]₁= 0.46

S₁= 0.93

X₂: pain measurement using a visual analog scale of an individual of the control groups.

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n₂= 20

X[bar]₂= 0.41

S₂= 1.26

The claim is that the pain reductions of the control group have more variation than the pain reductions of the target group. If it's so then we could suspect that the population variance of the control group, σ₂², will be greater than the population variance of the magnet group, σ₁².

To test the relationship between these two population variances you have to conduct a variance ratio test using the Snedecors F statistic.

The hypotheses are:

H₀: σ₂² ≤ σ₁²

H₁: σ₂² > σ₁²

α: 0.05

F= (\frac{S_2^2}{S_1^2}) * (\frac{Sigma_2^2}{Sigma_1^2} )~~ F_{(n_2-1);(n_1-1)}

This hypothesis test is one-tailed to the right, there is only one critical value:

F_{(n_2-1);(n_1-1); 1 - \alpha } = F_{19;19; 0.95}= 2.17

The decision rule for the test is:

If F_{H_0} ≥ 2.17, then the decision is to reject the null hypothesis.

If F_{H_0} < 2.17, then the decision is to not reject the null hypothesis.

F_{H_0}= \frac{S_2^2}{S_1^2}*\frac{Sigma_2^2}{Sigma_1^2}  = \frac{(1.26)^2}{(0.93)^2} * 1

F_{H_0} = 1.835 = 1.84

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I hope it helps!

3 0
3 years ago
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