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Salsk061 [2.6K]
3 years ago
14

Pls help with this question 1-5 thanks

Mathematics
1 answer:
belka [17]3 years ago
5 0

maybe 1/5 (409) ::(880) 1+2

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a woman spent two thirds of her money. she lost two thirds of the remiander and then had $4(aus money) left. how much money did
antiseptic1488 [7]

Step-by-step explanation:

2/3 lost is 1/3 kept

2/3 of the 1/3 kept is 2/9 lost

1/3 x - 2/9 x = 4

3/9 x - 2/9 x = 4

1/9 x = 4

x = 36

First she lost 2/3 of 36, which is 24. She had 12 left. Then she lost 2/3 of 12 which is 8. She had 4 left.

8 0
2 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. <br> IM GIVING 40 POINTS !! DONT SKIP :((.
Tomtit [17]
M = 44
b = 48
Equation: y = 44x + 48

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5 0
3 years ago
Find an equation of the line that passes through the points (-5, -3) and (3, 1)
Mkey [24]

\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-3})\quad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-5)}}}\implies \cfrac{1+3}{3+5}\implies \cfrac{4}{8}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{1}{2}}[x-\stackrel{x_1}{(-5)}]\implies y+3=\cfrac{1}{2}(x+5) \\\\\\ y+3=\cfrac{1}{2}x+\cfrac{5}{2}\implies y=\cfrac{1}{2}x+\cfrac{5}{2}-3\implies y = \cfrac{1}{2}x-\cfrac{1}{2}

6 0
3 years ago
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Which expression can be used to check the answer to 56 divided by (negative 14) = n?
allochka39001 [22]
D because n= -14 and were dividing 56
3 0
3 years ago
A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65m/s in 5 seconds what
artcher [175]

The acceleration is defined as the ratio between the change in velocity and the time elapsed to perform such a change.

These "changes" are indicated with the capital greek letter delta, \Delta, and when you write \Delta x you mean the difference between the finial and the inital values of the variable x:

\Delta x = x_{\text{fin}} - x_{\text{init}}

So, the acceleration is defined as

a = \dfrac{\Delta v}{\Delta t} = \dfrac{v_{\text{fin}} - v_{\text{init}}}{t_{\text{fin}} - t_{\text{init}}}

In this case, the initial velocity is 35, the final velocity is 65. Assuming we start the clock at the beginning of the observation, the inital time is 0 and the final time is 5. So, we have

a = \dfrac{65-35}{5-0} = \dfrac{30}{5} = 6m/s^2

3 0
3 years ago
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