Pls help with this question 1-5 thanks

Marcus' employee benefits include family health care coverage. He contributes 25% of the cost. Marcus gets paid weekly and $102

ArbitrLikvidat [17]

Monthly amount, M = $102×4 = $408.

Also, yearly amount, Y = M×12 = $408×12 = $4896

It is given that 25% of the cost is contributed by Marcus.

Amount Marcus paid

$=\dfrac{\$4896 \times 25 }{100}\\\\= \$1224$

Therefore, his employer contribution annually for coverage is $( 4896 - 1224)=$3672.

Hence, this is the required solution.

4 0

3 years ago

HELPP now plssss!!!!!

Bumek [7]

So go down and up then look it up on the web so you can look good in it that really helps

7 0

2 years ago

On Melissa's 6th birthday, she gets a $2000 CD that earns 7% interest compounded quarterly. If the CD matures on her 13th birthd

Alexandra [31]

Answer:

$A\simeq3250.83$

Step-by-step explanation:

The amount formula in compound interest is:

$A=P(1+\frac{r}{n} )^{nt}$

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $2000

$r = 7\% = \frac{7\%}{100\%}=0.07$

t = 7 (number of years from 6th to 13th bday)

n = 4 (quarterly in a year)

Then,

$A=2000(1+\frac{0.07}{4} )^{(4)(7)}\\\\A=2000(1+\frac{0.07}{4} )^{28}\\\\A=3250.825792\\\\A\simeq3250.83$

8 0

2 years ago

A. [4 marks]

storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is $u_{n}=u_{1}+(n-1)d$ , where

$u_{1}$ is the first term
d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is $u_{n}=u_{1}r^{n-1}$ , where

$u_{1}$ is the first term
r is the common ratio between each two consecutive terms $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∵ $u_{1}$ of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ $u_{2}$ , $u_{3}$ , $u_{6}$ are the first 3 terms of a geometric sequence

∵ $u_{2}$ = 1 + (2 - 1)d

∴ $u_{2}$ = 1 + d

∵ $u_{3}$ = 1 + (3 - 1)d

∴ $u_{2}$ = 1 + 2d

∵ $u_{6}$ = 1 + (6 - 1)d

∴ $u_{2}$ = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

(1 + 5d)

∵ The common ratio in the geometric sequence is $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∴ $r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

- Use cross multiplication with the equal fractions

∵ $\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0

3 years ago

What is 0.1 repeating as a fraction

marta [7]

Answer:1/9

Step-by-step explanation:

5 0

3 years ago