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Salsk061 [2.6K]
3 years ago
14

Pls help with this question 1-5 thanks

Mathematics
1 answer:
belka [17]3 years ago
5 0

maybe 1/5 (409) ::(880) 1+2

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Marcus' employee benefits include family health care coverage. He contributes 25% of the cost. Marcus gets paid weekly and $102
ArbitrLikvidat [17]

Monthly amount, M = $102×4 = $408.

Also, yearly amount, Y = M×12 = $408×12 = $4896

It is given that 25% of the cost is contributed by Marcus.

Amount Marcus paid

=\dfrac{\$4896 \times 25 }{100}\\\\= \$1224

Therefore, his employer contribution annually for coverage is $( 4896 - 1224)=$3672.

Hence, this is the required solution.

4 0
3 years ago
HELPP now plssss!!!!!
Bumek [7]
So go down and up then look it up on the web so you can look good in it that really helps
7 0
2 years ago
On Melissa's 6th birthday, she gets a $2000 CD that earns 7% interest compounded quarterly. If the CD matures on her 13th birthd
Alexandra [31]

Answer:

A\simeq3250.83

Step-by-step explanation:

The amount formula in compound interest is:

A=P(1+\frac{r}{n} )^{nt}

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $2000

r = 7\% = \frac{7\%}{100\%}=0.07

t = 7 (number of years from 6th to 13th bday)

n = 4 (quarterly in a year)

Then,

A=2000(1+\frac{0.07}{4} )^{(4)(7)}\\\\A=2000(1+\frac{0.07}{4} )^{28}\\\\A=3250.825792\\\\A\simeq3250.83

8 0
2 years ago
A. [4 marks]
storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is u_{n}=u_{1}+(n-1)d , where

  • u_{1} is the first term
  • d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is u_{n}=u_{1}r^{n-1} , where

  • u_{1} is the first term
  • r is the common ratio between each two consecutive terms r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∵ u_{1} of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ u_{2} , u_{3} , u_{6} are the first 3 terms of a geometric sequence

∵ u_{2} = 1 + (2 - 1)d

∴ u_{2} = 1 + d

∵ u_{3} = 1 + (3 - 1)d

∴ u_{2} = 1 + 2d

∵ u_{6} = 1 + (6 - 1)d

∴ u_{2} = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

   (1 + 5d)

∵ The common ratio in the geometric sequence is r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∴ r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

- Use cross multiplication with the equal fractions

∵ \frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0
3 years ago
What is 0.1 repeating as a fraction​
marta [7]

Answer:1/9

Step-by-step explanation:

5 0
3 years ago
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