Assuming that you want to add or subtract them and want the bottom number the same,
1/4 and 2/3
least common multiple of 4 and 3
4=2 times 2
3=3 times 1
so the leas common mulltiple will include all of them
the number is 2 times 2 times 3 or 12
lcm=12
1/4 times 3/3=3/12
2/3 times 4/4=8/12
add or subtract 3 and 8
LCM=12
9514 1404 393
Answer:
$2038.85
Step-by-step explanation:
The value of the loan at that point is given by ...
A = P(1 +rt) . . . . . Principal P, rate r, time t (years)
A = $1850(1 + 0.1225·(10/12)) = $2038.85
Ricardo will have paid back $2038.85 at the end of the loan period.
_____
<em>Additional comment</em>
We assume that the loan accrues simple interest and that the amount due is the sum of principal and interest at the end of the loan period.
The question is not specific as to whether interest compounds, or whether intermediate (monthly) payments are made. There are many possible ways the loan could be repaid, generally involving different amounts for the different terms.
Answer:
4
Step-by-step explanation:
4 is the base of the equation and then as it goes on, you add 2* the point in the sequence -1
Answer:
1008pi
Step-by-step explanation:
the formula for volume of a cylinder is pi r squared h
V equals 144 * 7 * pi
6.
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
Step-by-step explanation:
![\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B8%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%7D)
Since there are eight y's in two groups we can take them out which turns into
:)
3.
