3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
Answer:


Step-by-step explanation:
Given

Required
Find all product of real values that satisfy the equation

Cross multiply:


Subtract 7 from both sides


Reorder

Multiply through by -1

The above represents a quadratic equation and as such could take either of the following conditions.
(1) No real roots:
This possibility does not apply in this case as such, would not be considered.
(2) One real root
This is true if

For a quadratic equation

By comparison with 



Substitute these values in 


Add 56 to both sides


Divide through by 4

Take square roots


Hence, the possible values of r are:
or 
and the product is:


Answer:
where
Step-by-step explanation:
Answer:
this is prime
Step-by-step explanation: