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MrRa [10]
4 years ago
5

Find the coordinates of the following points

Chemistry
1 answer:
sveta [45]4 years ago
3 0
If
(
a
,
b
)
is a are the coordinates of a point in Cartesian Plane,
u
is its magnitude and
α
is its angle then
(
a
,
b
)
in Polar Form is written as
(
u
,
α
)
.
Magnitude of a cartesian coordinates
(
a
,
b
)
is given by
√
a
2
+
b
2
and its angle is given by
tan
−
1
(
b
a
)
Let
r
be the magnitude of
(
−
2
,
5
)
and
θ
be its angle.
Magnitude of
(
−
2
,
5
)
=
√
(
−
2
)
2
+
5
2
=
√
4
+
25
=
√
29
=
r

Angle of
(
−
2
,
5
)
=
tan
−
1
(
5
−
2
)
=
tan
−
1
(
−
5
2
)
=
−
68.198
degree
⇒
Angle of
(
−
2
,
5
)
=
−
68.198
degree
But since the point is in second quadrant so we have to add
180
degree which will give us the angle.
⇒
Angle of
(
−
2
,
5
)
=
−
68.198
+
180
=
111.802
⇒
Angle of
(
−
2
,
5
)
=
111.802
=
θ
⇒
(
−
2
,
5
)
=
(
r
,
θ
)
=
(
√
29
,
111.802
)

⇒
(
−
2
,
5
)
=
(
√
29
,
111.802
)

Note that the angle is given in degree measure.
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Explanation:

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A photon has an energy of 1.10 x 10 -13 j. What is the photon's wavelength? What type of electromagnetic radiation is it?
lawyer [7]

Answer:

λ  = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

Explanation:

Given data:

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Wavelength of photon = ?

Solution:

Formula:

E = h.c / λ

λ  = h. c / E

λ  = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.

λ  = 19.878 × 10⁻²⁶m /  1.10 × 10⁻¹³ J

λ  = 18.071 × 10⁻¹³ m

λ  = 18.071 × 10⁻¹³  × 10⁹

λ  = 18.071 × 10⁻⁴ nm

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3 0
4 years ago
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yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

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m = mass of the object

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a =\frac{F}{m}

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F = 8 N

a =\frac{8}{2}

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B) The box with the mass of 4kg

a =\frac{8}{4}

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3 0
4 years ago
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sammy [17]

Explanation:

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            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

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Therefore, electrostatic repulsive force on proton is calculated as follows.

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Putting the given values into the above formula as follows.

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              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
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