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Oduvanchick [21]
3 years ago
15

This is very urgent please hurry!!?!!??!

Chemistry
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

a =\frac{F}{m}

A) The box with a mass of 2kg

F = 8 N

a =\frac{8}{2}

a = 4 m/s2

B) The box with the mass of 4kg

a =\frac{8}{4}

a = 2 m/s2

C) The box with a mass of 6kg

a =\frac{8}{6}

a = 1.33 m/s2

D) The box with a mass of 8kg

a =\frac{8}{8}

a = 1 m/s2

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Evgesh-ka [11]
<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})
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<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

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