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77julia77 [94]
3 years ago
13

Solve the simultaneous equations. xy = 4x + y = 5​

Mathematics
2 answers:
lozanna [386]3 years ago
6 0

Answer:

1,4

4,1

Step-by-step explanation:

y = 4/x

substitute

x + 4/x = 5

multiply the whole thing by x to make life easier

x^2 +4 = 5x

X^2 -5x +4 = 0

(x-1)(x-4)=0

x-1=0 x =1

x-4 =0. x=4

so there are 2 solutions

x=1. y = 4

x =4. y =1

Maru [420]3 years ago
5 0
Answer:
if X=1 ; Y=4
if X=4 ; Y=1
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When I triple my number and add five I get twenty six what is my number
fenix001 [56]

26-5=21

21/3=7

7 is your number

to check work

3*7=21+5=26

3 0
3 years ago
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There is a lightning rod on top of a building. From a location 500 feet from the base of the building, the angle of elevation to
Kitty [74]
<h2>Hello!</h2>

The answer is:

The height of the  lightning rod is 27.4 feet.

<h2>Why?</h2>

To solve the problem, we need to use the given information about the two points of observation, since both are related (both finish and start at the same horizontal distance) we need to write to equations in order to establish a relationship.

So, writing the equations we have:

We know that the angle of elevation from the base of the buildings is 36°

Also, we know that from the same location, the angle of elevation to the top of the lightning rod is 38°.

Using the information we have:

To the top of the building:

tan(\alpha )=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}

To the top of the lightning rod:

tan(\alpha )=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}

Now, isolating we have:

tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\DistanceToTheTopOfTheBuilding=tan(36\°)*BuildingBase \\\\DistanceToTheTopOfTheBuilding=tan(36\°)*500feet=363.27feet

Also, we have that:

tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*BuildingBase\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*500feet=390.64feet

Therefore, if we want to calculate the height of the lightning rod, we need to do the following:

Let "x" the distance to the top of the building and "y" the distance to the top of the lightning rod, so:

LightningRodHeight=y-x=390.64feet-363.27feet=27.37feet

Rounding to the nearest foot, we have:

LightningRodHeight=y-x=390.64feet-363.27feet=27.37feet=27.4feet

Hence, the answer is:

The height of the lightning rod is 27.4 feet.

Have a nice day!

5 0
3 years ago
Subtract the following polynomials, then place the answer in the proper location on the grid.
Grace [21]
(3m - 4n - 7) - (8m + n - 6)

3m - 8m  = - 5m
-4n - n = -5n
-7 - (-6) = -7 + 6 = -1

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hope this helps
8 0
3 years ago
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} is your average rate of change,

Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
2 years ago
Given: ABC , BD is an<br> altitude to side AC, &amp; D is a midpoint<br> Prove: AB BC
Over [174]

Answer:

steps below

Step-by-step explanation:

BD⊥AC    ∠ADB = ∠CDB = 90°

D is mid-point: AD = CD

BD = BD

ΔADB ≅ ΔCDB

AB = BC

5 0
2 years ago
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