Light behaves like both waves and particles.
The angular momentum of a rotation object is the product of its moment of inertia and its angular velocity:
L = Iω
L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Apply the conservation of angular momentum. The total angular momentum before disks A and B are joined is:
L_{before} = (3.3)(6.6) + B(-9.3)
L_{before} = -9.3B+21.78
where B is the moment of inertia of disk B.
The total angular momentum after the disks are joined is:
L_{after} = (3.3+B)(-2.1)
L_{after} = -2.1B-6.93
L_{before} = L_{after}
-9.3B + 21.78 = -2.1B - 6.93
B = 4.0kg·m²
The moment of inertia of disk B is 4.0kg·m²
Answer:
A. 1.125×10^-7 kgm^2
B. 6.64875 rad/s
Explanation:
The moment of inertia is defined as a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.
A. Moment of inertia = m1✖r1^2
=1.80 x (2.5x10^-4)^2
= 6.25x10^8 x 1.80
= 1.125 x 10^-7 kgm^2.
B. w is represented as Angular speed.
V is velocity, T is time in period.
Velocity= distance / time.
V= 2.5x10^-4 / 0.940
V= 2.6595 metre per seconds
w= v/r
w= 2.6595 / 0.400
w= 6.64875 rad/s.
I'm pretty sure B would be your answer.
