All categories

3 years ago

Which option lists a form of potential energy followed by a form of kinetic energy?

Physics

2 answers:

Serjik [45]3 years ago

6 0

Answer:

its B

Explanation:

Nadusha1986 [10]3 years ago

4 0

Answer:

Magnetic energy and electromagnetic energy form of potential energy followed by a form of kinetic energy.

(B) is correct option.

Explanation:

Given that,

Lists a form of potential energy followed by a form of kinetic energy

We know that,

Sound energy :

The movement of energy through object it is called sound energy. When a object produced vibration by force then it moves in wave.

Sound wave is example of kinetic energy.

Nuclear energy :

The store energy in the nucleus of the atom it is called nuclear energy. This energy released when occurs fusion and fission.

Nuclear energy is the example of potential energy

Magnetic energy :

Magnetic energy is a type of potential energy which is depend on distance and position in the magnetic field.

Electromagnetic energy :

Electromagnetic energy is light energy. it is type of kinetic energy.

Gravitational energy :

Gravitational energy is a type of potential energy. It is an energy related with gravity or gravitational force.

Elastic energy :

The store energy in elastic object it is called elastic energy. This energy is a type of potential energy.

Electrical energy :

The movement of electrons is called electrical energy. When electrons move through a wire then it is are called electricity. Electrical energy is type of kinetic energy.

Hence, Magnetic energy and electromagnetic energy form of potential energy followed by a form of kinetic energy.

(B) is correct option.

You might be interested in

Discuss the difference between waveform graphs and vibration graphs

Kitty [74]

Difference exists mainly in the label for x axis.

Explanation:

Shapes of waveform and vibration graphs are same.
Vibration graphs shows the particle at a single location in the path of the wave when time passes.
Waveform graphs shows the particle at multiple locations at a single moment of time.

6 0

3 years ago

PLEASE HELP!! 13 POINTS! SCIENCE!

pogonyaev

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

Calculate the magnitude of the acceleration due to gravity on the surface of Earth due to the Moon.

Fudgin [204]

Answer:

$g'_h=1.096\times 10^{-5}\ m.s^{-2}$

Explanation:

We know that the gravity on the surface of the moon is,

$g'=\frac{g}{6}$

$g'=1.63\ m.s^{-2}$

<u>Gravity at a height h above the surface of the moon will be given as:</u>

$g'_h=\frac{G.m}{(r+h)^2}$ ..........................(1)

where:

G = universal gravitational constant

m = mass of the moon

r = radius of moon

We have:

$G=6.67\times 10^{-11}\ m^3.s^{-2}.kg^{-1}$

$m=7.35\times 10^{22}\ kg$

$r=1.74\times 10^6\ m$

$h=384.4\times 10^6\ m$ is the distance between the surface of the earth and the moon.

Now put the respective values in eq. (1)

$g'_h=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.74\times 10^6+384.4\times 10^6)^2}$

$g'_h=1.096\times 10^{-5}\ m.s^{-2}$ is the gravity on the moon the earth-surface.

4 0

3 years ago

A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un

KonstantinChe [14]

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

$x=vt=23.3\frac{m}{s}t$

and the police car distance:

$x=vt+\frac{at^{2}}{2}=0+\frac{2.75\frac{m}{s^{2}} t^{2}}{2}=0.73\frac{m}{s^{2}}$

Since they both travel the same distance x, we can equal both formulas and solve for t:

$0 = 0.73\frac{m}{s^{2}}t^{2}-23.3\frac{m}{s} t\\\\0=t(0.73\frac{m}{s^{2}}t-23.3\frac{m}{s} )\\\\$

Two solutions exist to the equation; the first one being $t=0$

The second solution will be:

$0.73\frac{m}{s^{2}}t=23.3\frac{m}{s}\\\\t=\frac{23.3\frac{m}{s}}{0.73\frac{m}{s^{2}}}=32s$

This result allows us to confirm that the police car will take 32s to catch up to the speeder

7 0

3 years ago

Where do you feel that you are traveling at the fastest speed when on the swing?

il63 [147K]

Answer:

Explanation:

I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.

7 0

3 years ago

Read 2 more answers