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timofeeve [1]
4 years ago
10

Please help!! The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of

the average speed of the particle between t = 1.0 s and t = 4.0 s?

Physics
1 answer:
Bogdan [553]4 years ago
6 0

Answer:

1.3 m/s

Explanation:

average speed = total distance/ total time

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If Rebecca is traveling at 7 m/s east for 1 hour how much is Rebecca displaced
Mekhanik [1.2K]

Answer:

25.2 km east

Explanation:

The relationship between velocity and displacement is given by:

v=\frac{d}{t}

where

v is the velocity

d is the displacement

t is the time

In this problem, we have:

v=7 m/s east is Rebecca's velocity

t=1 h=60 min=3600 s is the time taken

Re-arranging the equation, we can find Rebecca's displacement:

d=vt=(7 m/s)(3600 s)=25,200 m=25.2 km

and the direction is same as velocity (east)

3 0
3 years ago
Two asteroids collide and stick together. The first asteroid has mass of 1.50 × 104 kg andis initially moving at 0.77 × 103 m/s.
KengaRu [80]

Answer:

Magnitude 900m/s, direction 12.8° respect to the velocity of the first asteroid.

Explanation:

This is a perfectly inelastic collision, because the two asteroids stick together at the end. That means that the kinetic energy doesn't conserves, but the linear momentum does. But, since the velocities of the asteroids have different directions, we have to break down them in components. For convenience, we will take the direction of the first asteroid as x-axis, and its perpendicular direction  (in the plane of the two velocity vectors) as y-axis. So, we have that:

p_{1ox}+p_{2ox}=p_{fx}\\\\p_{2oy}=p_{fy}

And, since p=mv, we get:

m_1v_{1o}+m_2v_{2o}\cos\theta=(m_1+m_2)v_{fx}\\\\m_2v_{2o}\sin\theta=(m_1+m_2)v_{fy}

Solving for v_fx and v_fy, and calculating their values, we get:

v_{fx}=\frac{m_1v_{1o}+m_2v_{2o}\cos\theta}{m_1+m_2}\\\\\implies v_{fx}=\frac{(1.50*10^{4}kg)(0.77*10^{3}m/s)+(2.00*10^{4}kg)(1.02*10^{3}m/s)\cos20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=878m/s\\\\\\v_{fy}=\frac{m_2v_{2o}\sin\theta}{m_1+m_2}\\\\\implies v_{fy}=\frac{(2.00*10^{4}kg)(1.02*10^{3}m/s)\sin20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=199m/s

Now, the final speed can be calculated using the Pythagorean Theorem:

v_f=\sqrt{v_{fx}^{2}+v_{fy}^{2}} \\\\\implies v_f=\sqrt{(878m/s)^{2}+(199m/s)^{2}}=900m/s

And the direction \beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°can be obtained using trigonometry:

\beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°

That means that the final velocity of the two asteroids has a magnitude of 900m/s and a direction of 12.8° with respect to the velocity of the first asteroid.

7 0
3 years ago
Aluminum foil has a shiny side and a dull side. Many experts believe that the shiny side of the aluminum foil should face the fo
hjlf
The answer is radiation
8 0
4 years ago
Read 2 more answers
Engineers are starting on a new project to develop technology. Which of these
Ilya [14]
The answer should be C. In this question
3 0
3 years ago
A race car weighs 6958 N. What is its mass?
Eddi Din [679]

Answer:

710kg

Explanation:

Given parameters:

Weight of race car = 6958N

Unknown:

Mass of the race car  = ?

Solution:

The weight of a body is the force of gravity acting on that body. It is mathematically expressed as:

  Weight  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

  6958 = mass x 9.8

        mass  = 710kg

4 0
3 years ago
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