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user100 [1]
3 years ago
12

Plz help meee <3 kitty’s

Mathematics
2 answers:
Murrr4er [49]3 years ago
4 0

Answer:

linear means a line (that eliminates c and d)

as "X" increases the "Y" value "DECREASES" so the answer is "B"

Step-by-step explanation:

Mademuasel [1]3 years ago
4 0

Answer:

B. Linear decreasing

Step-by-step explanation:

The graph appears to have a negative slope, and it is a straight line. This means the graph will be linear. An exponential growth/decay would have a curved line, so those are automatically out. Since the farther the points go the more downwards the line is, this means it is decreasing.

hope this helped. :)

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Answer:

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Step-by-step explanation:

These are the equations you build from the problem:

h + s = 152

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This is how I solved them:

s= 152-h

8.5h + 12(152-h) = 1656

8.5h + 1824 - 12h = 1656

Solve for h

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Put this into first equation (h +s = 152) to get s

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The estimate of the problem would be 1/4 because 6/8- 1/2 you would get 1/4. 
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2 years ago
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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

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(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

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It may be useful in areas where there is a lot of recorded information. The analysis relies on the simultaneous application of statistics, computer programming, and operations research to quantify performance.

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