Answer:
46lb
Step-by-step explanation:
you take twenty five divide by one twenty
A number that is not a whole number.
The derivative of a variable raised to exponent of n, x^n is equal to the product of n and x raised to exponent of n-1.
d(x^n) = (n)(x^n-1)
So, from the given
d(9x + 5) = (1)(9x^1-0) + 5(0)
= 9
The given value of x is irrelevant to this item because the derivative does not contain any variable x.
Ok, so you have your equation, 5·x+5-(5x+25).
First, do the prathases, so you have, 5x+5-5x-25.(5·x also means 5x)
Now, you need to combine like terms, and through that the xs cancel out, so you are left with -20 as you answer.
