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SOVA2 [1]
3 years ago
13

Which type of function has an x as the exponent?*

Mathematics
2 answers:
diamong [38]3 years ago
4 0

Answer:

Exponential Equations

These equations have variables in the exponent. Such as this one:

63+5^{x}

andrey2020 [161]3 years ago
3 0

Answer:

Exponential functions

Step-by-step explanation:

:D

You might be interested in
What is -20 and 3/4 as a decimal.
REY [17]

Answer:

20.75

Explanation:

20+3/4

= 20.75

= 2075

6 0
3 years ago
HELP
Ket [755]

Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.

<h3>How can the duration of signal reception be found?</h3>

Radius of broadcast of the transmitter = 50 miles

Location of starting point = 56 miles north of the transmitter

Location of destination city = 58 miles east of the transmitter

Therefore we have;

Slope of the line joining the two cities

= 56 ÷ (-58) = -0.966

Which gives the equation of the line as follows;

y = -0.966•x + 56

The equation of the circle is;

{x}^{2}  +  {y}^{2}  =  {50}^{2}

{x}^{2}  +  { ( - 0.966x + 56)}^{2}  =  {50}^{2}

1.933156•x^2 - 108.192•x + 636 = 0

Which gives;

  • x = 6.67 or x = 49.29

Therefore;

When x = 6.67, we have;

  • y = -0.966 × 6.67 + 56 = 49.56

When x = 49.29, we have;

  • y = -0.966 × 49.29 + 56 = 8.4

The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;

l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>

  • The length of the drive during which the signal is received is 59.24 miles

Learn more about the equation of a circle here:

brainly.com/question/502872

#SPJ1

5 0
2 years ago
Help with homework please? Not asking for answers, but want to learn how to do these.
Ivahew [28]
Hi there!

Since you said that you didn't want answers, I'll try my best to just explain things to you. However, if you'd like to work on problems, just let me know and I'd be happy to help you find answers.

SIMPLIFY THE SUM OR DIFFERENCE:
For these, what you can do is get all of the numbers to the same form. Such as simplifying the square root of 64 to 8. This will help you to be able to add or subtract things easily. The only time that you can subtract or add things is if whatever is under the square root is the same.

SIMPLIFY THE PRODUCT:
For these, you need to first multiply or distribute. You multiply both the numbers and the square roots. However, what is under the square root stays underneath the square root until you simplify it.

SIMPLIFY THE QUOTIENT:
These can be tricky sometimes. What you need to do is first, get the top and bottom as simplified as you can. Then, begin getting rid of the same things, as they cancel each other out. Once you've simplified as much as you can, make sure there isn't a square root in the denominator. There should never be one there! To get rid of it, multiply the top and bottom by whatever is under the square root on the bottom. For example, if I had 5/squareroot(10), then I would multiply the top and bottom by squareroot(10) to get rid of the square root in the denominator.

SIMPLIFY THE EXPRESSION:
To simplify the expression, most times all you need to do is distribute and possibly subtract or add (sometimes). The only time you can add or subtract square root is if (what is under the square root) is the same. If they are not the same, then you do not need to worry about further simplifying as there is nothing else that you can do.

Hope this helps!! :)
Message me anytime if there's anything else that I can help you with!
5 0
3 years ago
Alex has 7 pounds of birdseed and 5 bird feeders.
hram777 [196]
Well, we dont know because we cant see the barmodels
5 0
3 years ago
PLSSSSSS HELP <br> BRAINLIST
Helga [31]

Answer:

The step 4 is not what he should have done. But the wrong is step 5, because if he added -2x both sides, it would give the following equation:

x-12=-4x+6

and not x-12=6

Note that in step 4 he should have added 2x and not -2x to both sides, but we still have the equality. The problem is that step 5 is totally wrong.

I don't know what answer is expected to this question, but I would mark step 5, because this is mathematically wrong.  

Solving the equation

3(x-4)=-4-2(x-5)

Using distribution

3x-12=-4-2x+10\\3x-12=-2+6

Add 2x both sides

3x-12+2x=-2x+6+2x

5x-12=6

Add 12 both sides

5x-12+12=6+12\\5x=18

Divide both sides by 5

$x=\frac{18}{5} $

4 0
3 years ago
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