Answer:
1.5 × 10⁻¹¹ M
Explanation:
Step 1: Given data
- Concentration of OH⁻ ([OH⁻]): 6.6 × 10⁻⁴ M
- Concentration of H⁺ ([H⁺]): ?
Step 2: Consider the self-ionization of water
H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)
Step 3: Calculate the molar concentration of H⁺
We will use the equilibrium constant for the self-ionization of water (Kw).
Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]
[H⁺] = 1.0 × 10⁻¹⁴ / [OH⁻]
[H⁺] = 1.0 × 10⁻¹⁴ / 6.6 × 10⁻⁴
[H⁺] = 1.5 × 10⁻¹¹ M
Answer:
9. Electron Affinity
10. The second option....
3H2+N2→2NH3
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
A. Dalton's theory that atoms could not be divided was incorrect
