Answer:
1) When 69.9 g heptane is burned it releases 5.6 mol water.
2) C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.
Explanation:
- Firstly, we should balance the equation of heptane combustion.
- The balanced equation is: <em>C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.</em>
This means that every 1.0 mole of complete combustion of heptane will release 8 moles of H₂O.
- We need to calculate the no. of moles in 69.9 g of heptane that is burned using the relation: <em>n = mass/molar mass.</em>
n of 69.9 g of heptane = mass/molar mass = (69.9 g)/(100.21 g/mol) = 0.697 mol ≅ 0.7 mol.
<em><u>Using cross multiplication:</u></em>
1.0 mol of heptane releases → 8 moles of water.
0.7 mol of heptane releases → ??? moles of water.
<em>∴ The no. of moles of water that will be released from burning (69.9 g) of water</em> = (0.7 mol)(8.0 mol)/(1.0 mol) = <em>5.6 mol.</em>
<em>∴ When 69.9 g heptane is burned it releases </em><em>5.6</em><em> mol water. </em>
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Answer:
D)
Explanation:
I just answered the question and got it right.
Might be false
Hope so
So sorry if it is wrong
Answer:
The ranking order of the degree of polarity is HF>HCl>HBr>HI
Explanation:
The degree of polarity of a compound depends on the nature electronegative atom that it contains.
Among Fluorine,chlorine,bromine and iodine the electronegativity of fluorine is highest among all the mentioned atoms.
Due to high electronegativity HF is the most polar than HCl,HBr and HI and the HI have least polarity as its atomic structure is large and electronegativity is lower than fluorine,chlorine and bromine.
Answer:
group 1, 2 and 3 tend to get rid of electrons and start to form compounds with groups 7, 6, and 5.
Explanation:
