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3 years ago

Make a poem about waves with 12 Lines and 3 Stanzas.

Physics

2 answers:

Hoochie [10]3 years ago

6 0

In a ocean full of storms

A new wave was born

Deep into that darkness flooding

Suddenly, I heard some pummeling

By the grave I saw the winds

And the sun just shined

ioda3 years ago

6 0

Answer:

a friendly face that comes with waves,

the waves of all the memorial days,

and with these days we smile with pride,

as for the waves we used to ride,

given up the day has passed,

how it went away like an hour glass,

as if we knew the world was right,

just like the waves, oh so bright,

the time has come the days have passed,

the waves ashore the waves alast,

as if the friendly face was right,

the waves that rode, oh goodnight.

You might be interested in

A force that varies with time is applied to an object. The force increases linearly from zero to twenty-four newtons during the

harkovskaia [24]

Answer:

144Ns

Explanation:

Impulse is the product of force and change in time or a measure of the change in momentum. Mathematically, Impulse is given as

J = FΔt

Where

J = Impulse,

F = Force,

Δt = change in time.

Due to the varying force, we know that the impulse varies at different points in the motion. Hence, the Net Impulse will be the addition of the individual impulses, i.e.

J = ΣJᵢ

J = J₁ + J₂ + J₃

J = F₁Δt₁ + F₂Δt₂ + F₃Δt₃

=> J = (24*2) + (24*4) + (0*2)

J = 48 + 96 + 0

J = 144 Ns

4 0

3 years ago

The weight of a girl with the mass of 40.0kg is ?

Allushta [10]

Answer:

392 Newtons

Explanation:

In order to find the weight, you have to multiply the mass by the gravitation constant (9.8), which gives us 40.0 * 9.8 = 392 Newtons.

4 0

3 years ago

At the end of a delivery ramp, a skid pad exerts a constant force on a package so that the package comes to rest in a distance d

MatroZZZ [7]

Answer:

increases by a factor of $\sqrt{2}$

Explanation:

First we need to find the initial velocity for it to stop at the distance 2d using the following equation of motion:

$v^2 - v_0^2 = 2a\Delta s$

where v = 0 m/s is the final velocity of the package when it stops, $v_0$ is the initial velocity of the package when it, a is the deceleration, and $\Delta s = d$ is the distance traveled.

So the equation above can be simplified and plug in Δs = d, $v_0 = v_1$ for the 1st case

$-v_1^2 = 2ad$ (1)

For the 2nd scenario where the ramp is changed and distance becomes 2d, $v_0 = v_2$

$-v_2^2 = 4ad$ (2)

let equation (2) divided by (1) we have:

$\left(\frac{v_2}{v_1}\right)^2 = 4ad / 2ad = 2$

$v_2 / v_1 = \sqrt{2}$

$v_2 = \sqrt{2}v_1$

So the initial speed increases by $\sqrt{2}$ . If the deceleration a stays the same and time is the ratio of speed over acceleration a

$t = v / a$

The time would increase by a factor of $\sqrt{2}$

7 0

4 years ago

23 is 2% of what<br> number?

8_murik_8 [283]

Answer:

1;150

Explanation:

2% × ? = 23

? =

23 ÷ 2% =

23 ÷ (2 ÷ 100) =

(100 × 23) ÷ 2 =

2,300 ÷ 2 =

1,150;

7 0

3 years ago

Read 2 more answers

What is the speed of a 50 g rock if its de broglie wavelength is 3.32x10^-34m?

ivann1987 [24]

We can find the momentum of the rock by using De Broglie's relationship:
$p= \frac{h}{\lambda}$
where
p is the momentum
h is the Planck constant
$\lambda$ is the De Broglie's wavelength

By using $\lambda=3.32 \cdot 10^{-34} m$ , we find
$p= \frac{6.6 \cdot 10^{-34} Js}{3.32 \cdot 10^{-34} m}=1.99 kg m/s$

The momentum of the rock is
$p=mv$
where $m=50 g=0.05 kg$ is the mass and v is its velocity. Rearranging the equation, we find the speed of the rock:
$v= \frac{p}{m}= \frac{1.99 kg m/s}{0.05 kg}=39.8 m/s$

7 0

4 years ago