Answer:
Hope it helps
Explanation:
The higher the bird flies, the bigger the shadow it casts, however, for the shadow to be visible enough the plane or bird would have to be close to the line directly from the sun.
All are true except the first two.
Answer: option D. the ratio of the population of male deer is not constant.
Explanation:
The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.
These features are remarkable:
- The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.
This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.
- The population of female deer (purple or brown bars) decreases every decade.
This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.
- The populations never are equal, hence this discards the option C.
- Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.
Answer:
v’= 279.66 m / s
Explanation:
We work this exercise using the conservation of the moment. For this we define the system formed by the two blocks, therefore the forces during the collision are internal of the action and reaction type.
Initial instant. Before the crash
p₀ = m v₀ + 0
Final moment. After the crash
p_f = m v + M v ’
how the tidal wave is preserved
p₀ = p_f
m v₀ = m v + M v ’
v = 
let's calculate
v ’= 
v ’= 
v ’= 279.66 m / s
Answer:
a. Approximate umber of atoms = 10¹¹
b. number of atoms = 50 atoms thick
Note: The question is missing some parts. The complete question is as follows; Calculate the approximate number of atoms in a bacterium. Assume that the average mass of an atom in the bacterium is ten times the mass of a hydrogen atom. (Hint: The mass of a hydrogen atom is on the order of 1×10⁻²⁷ kg and the mass of a bacterium is on the order of 1×10⁻¹⁵ kg)
Explanation:
a. Approximate umber of atoms = mass of bacterium / 10 * mass of hydrogen
number of atoms = 10⁻⁵/ 10 × 10⁻²⁷
number of atoms = 10¹¹ atoms
b. The cell membrane is 10-8 m thick while the hydrogen atom has a diameter of 10-10 m.
The number of atoms in the cell membrane = d1 / 2 × d2
where d1 = diameter of cell membrane; d2 = diameter of hydrogen atom
The number of atoms in the cell membrane = 10⁻ / 2 × 10⁻¹⁰ = 50 atoms
