When we factorise an expression, we are looking for simple factors that multiply to get the original expression. Usually it is very natural to factorise something like a quadratic in x. For example:
x^2 + 3x + 2 = (x+1)(x+2)
But there are other situations where factorisation can be applied. Take this quadratic:
x^2 - 9x = x(x-9)
This second example is closer to the question in hand. Just like x was a common factor to both x^2 and -9x, we are looking for a common factor to both 6b and 24bc. The common factor is 6b.
Hence 6b + 24bc = 6b(1 + 4c).
I hope this helps you :)
Answer:
6
Step-by-step explanation:
Answer:
5.51 meters
Step-by-step explanation:
New cordinates are formed by adding 7 in x and subtracting 2 from y
A(−2, 2) =A ' (-2 +7 , 2 - 1 ) = A' (5,1)
B(−2, 4) = B' (-2 + 7 , 4 -1 )= B' (5,3)
C(2, 4) = C' (2 + 7 , 4 -1 )= C' (9,3)
<span>D(2, 2) D' (2 + 7 , 2 -1 ) = D' ( 9 , 1)</span><span>
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