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Mama L [17]
3 years ago
15

What color will the paper appear? Explain why?

Physics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

The answer is B

Explanation:

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Samburu the elephant has a mass of 1650kg. If each of his feet cover an area of .25 m^2, how much pressure does samburu exert on
lidiya [134]
Samburu's weight is (mass x gravity) = (1650kg x 9.8 m/s²) = 16,170 Newtons.

Samburu's contact area with the ground is (0.25 m²/hoof) x (4 hoofs) = 1 m² .

Pressure = (force) / (area) = (16,170 Newtons) / (1 m²) = 16,170 Pascal .
8 0
3 years ago
By what process do electromagnetic waves release electrons from the
lesya [120]

Answer:

A.) the photoelectric effect

Explanation:

4 0
3 years ago
Read 2 more answers
The air temperature over a lake decreases linearly with height after sunset, since air cools faster than water. The mean molar m
Afina-wow [57]

Answer: t = 0.878s

Explanation: Dear big brain

since your temperature decreases linearly, you can assume that your velocity should behave linearly too. Here this isn't exactly the case (cfr. formula). But there's another way to prevent endlessly boring calculus. Use the principle of interpolation. (x/v_surface + x/v_top)/2 = t.

This answer won't be exactly the same, but it's a quite good approx. You can use this eqation, hence you don't use large distances.

7 0
3 years ago
Read 2 more answers
A sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?
Alja [10]

Answer:

887.1Hz

Explanation:

Given parameters:

Speed of sound wave  = 330m/s

Wavelength  = 0.372m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

             Speed  = Frequency x wavelength

            330  = Frequency x 0.372

   Frequency  = 887.1Hz

5 0
3 years ago
A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev
tatuchka [14]

Answer:

W_f = 2.319 rad/s

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

L_i = L_f

so:

I_mW_m = I_sW_f

where I_m is the moment of inertia of the merry-go-round, W_m is the initial angular velocity of the merry-go-round, I_s is the moment of inertia of the merry-go-round and the child together and W_f is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = \frac{1}{2}M_mR^2

I = \frac{1}{2}(115 kg)(2.5m)^2

I = 359.375 kg*m^2

Where M_m is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2\pi rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

I_s = \frac{1}{2}M_mR^2+mR^2

I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2

I_s = 506.25kg*m^2

Finally we replace all the data:

(359.375)(3.2672) = (506.25)W_f

Solving for W_f:

W_f = 2.319 rad/s

7 0
3 years ago
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