(Pls give brainliest! :D)
Answer:
<em>B</em>
Step-by-step explanation:
<em>You know that the graph intercepts at the point of (4,-2)</em>
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<em>Where x = 4 and y = -2.</em>
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<em>This means that whenever you plug a value of x in the equation it should give the value of y.</em>
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<em>For example when you plug x= 4 into the equation (B), it should look like this.</em>
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<em>4- y = 6, solving for y gives us the value negative 2.</em>
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<em>This means that it does give us this point, however, as the graph shows us, both lines meet at the point which means that both equation should give us this point.</em>
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<em>If we substitute x = 4 in the second equation of b, we should be able to get 3(4) + 4y = 4. Solving for y gives us -2.</em>
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Hope this helps!
-<em>Yumi</em>
Answer: they are nice understanding
Step-by-step explanation:
Answer:
The LCL of the R-chart starts from the origin ( i.e. zero value ) while the LCL of an X -chart did not start from the origin
LCL of R-chart = 0 * 0.84533 = 0
LCL of R-chart = 75.128
Step-by-step explanation:
Given data:
number of observations = 15
sample size ( m ) = 6
sum of sample mean = 80.20 ounces
sum of sample range ( R ) = 12.68 ounces
Determine the control limits of an x-bar and R-chart
<em>for an R-chart </em>
LCL of R-chart = D3 * R(bar) ---- ( 1 )
where : m = 6 , D3 = 0 , R = 12.68
R(bar) = 0.84533
back to equation 1
LCL of R-chart = 0 * 0.84533 = 0
<em>for an X-chart </em>
LCL of X-bar) = ( mean ) - (m x R-bar)
= 80.20 - ( 6 * 0.84533 )
= 75.128
The LCL of the R-chart starts from the origin ( i.e. zero value ) while the LCL of an X -chart did not start from the origin
Answer: 1/3 E = W
Not sure if that's correct
