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rusak2 [61]
2 years ago
15

Hi, I'm stuck on the problem: Consider a resistor (R=1000 kΩ) and a capacitor (C=1μF) connected in series. This configuration is

connected in series to a battery with an emf of 10 V. Find the maximum voltage in [V] across the capacitor. Find the maximum charge on the capacitor in [µC]. How long will it take until the capacitor has a potential difference of 5 V?
Physics
1 answer:
galina1969 [7]2 years ago
4 0

Answer:

Following are the responses to the given choices:

Explanation:

The maximum pressure is 10 V from across condenser.

The highest charge mostly on condenser.

vc = 10\times 1\ mf\\\\

    = 10^{-5}\ C

The time it takes for the condenser to be 5 V different.

time = ln_2 \times 1000  \times 1mf

        =0 .69 \times  10^{-3}\  sec

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Answer:

Explanation:

Given

charge of first body q_1=2.5\ mu C

charge of second body q_2=-3.5\ mu C

Particle 1 is at origin and particle 2 is at x=0.6\ m

third Particle which charge +q must be placed left of 2.5\mu C because it will repel the q charge while -3.5\mu C will attract it

suppose it is placed at a distance of x m

F_{1q}=\frac{kq(2.5)}{x^2}

F_{2q}=\frac{kq(-3.5)}{(0.6+x)^2}

F_{1q}+F_{2q}=0

\frac{kq(2.5)}{x^2}+\frac{kq(-3.5)}{(0.6+x)^2}=0

\frac{kq(2.5)}{x^2}=\frac{kq(3.5)}{(0.6+x)^2}

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3 years ago
A car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver n
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Answer:

a) t1 = v0/a0

b) t2 = v0/a0

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Explanation:

A)

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0 = v0 - a0*t

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= (2v0^2)/a0 - v0^2/a0

= v0^2/a0

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