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hodyreva [135]
3 years ago
8

PLEASE HELPPPPPPPPPP I WILL GIVE YOU BRAINLIEST Catalina's class wants to determine if boys or girls recycled more paper each da

y. They set up separate recycling bins in the classroom and labeled them "Boys" and "Girls." The students then placed their paper items in the correct bins. Which of the following should the students do each day before emptying the bins?
Physics
1 answer:
hram777 [196]3 years ago
6 0

Answer:

what are the answer choices

Explanation:

i dont know the choices so i say count the stuff they recycle, and add the score to the days before.

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Two rigid tanks of equal size and shape are filled with different gases. The tank on the left contains oxygen, and the tank on t
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Answer:

The number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.

Explanation:

Given:

Molar mass of oxygen, M_O=32

Molar mass of hydrogen, M_H=2

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PV=nRT

where:

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V = volume of the gas

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T = temperature of the gas

∵n=\frac{m}{M}

where:

m = mass of gas in grams

M = molecular mass of the gas

∴Eq. (1) can be written as:

PV=\frac{m}{M}.RT

P=\frac{m}{V}.\frac{RT}{M}

        as: \frac{m}{V}=\rho\ (\rm density)

So,

P=\rho.\frac{RT}{M}

Now, according to given we have T,P,R same for both the gases.

P_O=P_H

\rho_O.\frac{RT}{M_O}=\rho_H.\frac{RT}{M_H}

\Rightarrow \frac{\rho_O}{32}=\frac{\rho_H}{2}

\rho_O=16\rho_H

∴The molecules of oxygen are more densely packed than the molecules of hydrogen in the same volume at the same temperature and pressure. So, <em>the number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.</em>

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The hardest part of the job is to find the right formula to use, and write it down. You've already done that ! The rest is just turning the crank until an answer falls out.

You wrote. E = m g h.
Beautiful.
Now divide each side by (g h), and you'll have the formula for mass:

m = E / (g h).

You know all the numbers on the right side. Just pluggum in, do the arithmetic, and you'll have the mass.
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