Answer:........... .. .....
Answer:
the emf will be
Explanation:
We have given radius of the coil r = 3.6 cm = 0.036 m
So area
Number of turns N = 600
Emf is given by
So the emf will be
through out the projectile motion the horizontal vilocity remains constant due the absence of the air resistance so the ans is 47.3
The magnification of an image is equal to the ratio of the image height to the object height.