Answer:
.72 mols of KCl
Explanation:
Read the explanation while looking at the picture.
We start with 89g because it's what they give us:
89g of KCIO3 will cancel out with 123g of KCIO3 (molar mass)
~Grams of KCIO3 are canceled out.~
That 123g of KCIO3 is the same as 1 mol of KCIO3
Then we use mole to mole ratio:
1 mol of KCIO3 equals 2 mols of KCIO3 -- 2 moles from the equation
The 2 mols of KCIO3 is equal to 2 mols of KCl (from equation)
Multiply the numbers on top. Multiply the numbers on the bottom. Then divide. You get:
This sounds confusing. But the picture below is the format.
The SAME COLOR are the ones that cancel out.
Answer:
The heat needed to warm 406.0 mg of cyclohexane from 33.5°C to 38.9°C is 209.22 Joules
Explanation:
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have mass of cyclohexane = m = 406.0 mg = 0.4060 g
( 1 mg =0.001 g)
Specific heat of cyclohexane = c = 1.85 J/g°CK
ΔT = 38.9°C - 33.5°C = 5.4°C =5.4+273.15 K = 278.55 K
Heat absorbed by the cyclohexane :
The heat needed to warm 406.0 mg of cyclohexane from 33.5°C to 38.9°C is 209.22 Joules
Answer:
options B,C and E are correct conditions for forming hydrogen bonds.
Explanation:
In order for particles to stick together or shows certain characteristics, there must be a bond of attractions that is making them to be able to stay together. Some of these attractions are strong while some are weak. The kind of attraction that is being considered in this question is the hydrogen bonding which is considered as part of the weak forces of attractions.
In order for hydrogen bonds to occur, there must be hydrogen atoms [option B is correct] and a much more electronegative elements such as oxygen, Fluorine and Nitrogen. Hence, option C is correct.
Since the Fluorine or oxygen or nitrogen have much more electronegative properties than hydrogen, it causes a partial negative charge on Fluorine or oxygen or nitrogen and a partial positive charge on the Hydrogen. Thus, option E is correct.
The balanced equation
2Na₃PO₄+3Ca(NO₃)₂⇒6NaNO₃+Ca₃(PO₄)₂
<h3>Further explanation</h3>
Given
Reaction
_Na3PO4+_Ca(NO3)2-->_NaNO3+_Ca3(PO4)2
Required
Balanced equation
Solution
Give a coefficient
aNa₃PO₄+bCa(NO₃)₂⇒cNaNO₃+Ca₃(PO₄)₂
Ca, left=b, right = 3⇒ b=3
P, left=a, right = 2⇒a=2
Na, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6
The equation becomes :
2Na₃PO₄+3Ca(NO₃)₂⇒6NaNO₃+Ca₃(PO₄)₂
Answer:
The correct appropriate will be Option 1 (Acid anhydrides are less stable than esters so the equilibrium favors the ester product.)
Explanation:
- Acid anhydride, instead of just a carboxyl group, is typically favored for esterification. The predominant theory would be that Anhydride acid is somewhat more volatile than acid. This is favored equilibrium changes more toward the right of the whole ester structure.
- Extremely responsive than carboxylic acid become acid anhydride as well as acyl chloride. Thus, for esterification, individuals were most favored.
The other options offered are not relevant to something like the scenario presented. So, the solution here is just the right one.
