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Klio2033 [76]
2 years ago
13

A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net

ionic equation for this reaction by filling in the blanks. The phase symbols and charges on species are already provided.
Complete and balance the net ionic equation for this reaction.
Chemistry
1 answer:
Leya [2.2K]2 years ago
3 0

Answer:

See explanation

Explanation:

The molecular equation shows all the compounds involved in the reaction.

The molecular equation is as follows;

2NaF(aq) + Pb(NO3)2(aq) -------> PbF2(s) + 2NaNO3(aq)

The complete ionic equation shows all the ions involved in the reaction

The complete ionic equation;

2Na^+(aq) + 2F^-(aq) + Pb^2+(aq) + 2NO3^-(aq) -------->PbF(s) + 2Na^+(aq) +2NO3^-(aq)

The net Ionic equation shows the ions that actually participated in the reaction

The net ionic equation is;

2F^-(aq) + Pb^2+(aq)--------> PbF(s)

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First, let's look at the equation of the reaction:

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The mole ratio of octane to oxygen is 2:25.

Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol

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Thus, octane is limiting.

Mole ratio of octane to carbon dioxide = 2:16.

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More on percent yield can be found here: brainly.com/question/17042787

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