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vfiekz [6]
3 years ago
11

g Tom's roommate Bob spilled crystal violet solution on his lab coat, and Tom offers to use some lye (sodium hydroxide solution)

to clean it off. Bob suggest diluting the lye with water, but Tom argues that the cleaning action will be faster if concentrated lye is used. Bob counters that the speed of cleaning doesn't depend on the concentration of the lye. Who is correct? Use your results to support your conclusion.
Chemistry
1 answer:
irina [24]3 years ago
4 0

Answer:

Tom is correct. The rate of reaction of Crystal violet and NaOH is first order with respect to NaOH, hence, a higher concentration of NaOH corresponds to a higher rate of reaction; a faster reaction.

This means the speed of cleaning depends on the concentration of the lye used.

Explanation:

The reaction between Crystal violet and NaOH, represented as

CV⁺ + OH⁻ → CVOH

It is a reaction that is know to turn the violet colour of the crystal violet colourless.

The rate of the reaction is also known to be second order; first order with respect to Crystal violet and first order with respect to NaOH.

This means that the rate of reaction is directly proportional to the concentration of NaOH provided all other parameters such as the rate constant and the concentration of Crystal violet are constant.

Hence, the reaction becomes faster with an increased concentration of NaOH.

So, Tom is right, concentrated lye solution would remove the stain faster.

Bob is wrong.

Hope this Helps!!!

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A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of magnesium fluoride in
mojhsa [17]

The question is incomplete, here is the complete question:

A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of chemist's working solution is 5.90\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock magnesium fluoride solution

M_2\text{ and }V_2 are the molarity and volume of chemist's magnesium fluoride solution

We are given:

M_1=0.00154M\\V_1=230mL\\M_2=?M\\V_2=600mL

Putting values in above equation, we get:

0.00154\times 230=M_2\times 600\\\\M_2=\frac{0.00154\times 230}{600}=5.90\times 10^{-4}M

Hence, the concentration of chemist's working solution is 5.90\times 10^{-4}M

8 0
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What happen when molten zinc bromide is electrolysised
worty [1.4K]

Answer:

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Explanation:

hope it helps

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