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klemol [59]
3 years ago
11

1. Alginate is

Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

Option b, Irreversible hydrocolloid impression material

Explanation:

Irreversible is used as an impression material to take impression from edentulous jaws. It is also used in wound healing and drug delivery.

Alginate is a natural polymer found in cell wall of brown seaweed.

Its monomers are β-D-mannuronate and α-L-guluronate.

In association with Ca2+, it forms gel. It is hydrophilic in nature.

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In which direction does a bag at rest move when a force of 20 newtons is applied from the right?
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5 properties of acids
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Answer:

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3 years ago
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A metal crystallizes in the face‑centered cubic (FCC) lattice. The density of the metal is 12020 kg/m3, and the length of a unit
Fantom [35]

Answer:

  1.7700×10^-22 g

Explanation:

A face-centered-cubic cell contains 4 atoms, so the volume per atom is ...

  (389.80×10^-12 m)³/(4 atoms) ≈ 1.4725×10^-29 m³

Then the mass of 1 atom is ...

  (12020 kg/m³)(1.4725×10^-29 m³) ≈ 1.76995×10^-25 kg

  ≈ 1.7700×10^-22 g

_____

<em>Additional comment</em>

That is the approximate mass of a Palladium atom.

7 0
3 years ago
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The electrolysis of water forms H2 and O2. 2H2O 2H2 + O2 What is the percent yield of O2 if 10.2 g of O2 is produced from the de
BigorU [14]

<u>Answer:</u> The percent yield of oxygen gas is 67.53 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of water = 17.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{17.0g}{18g/mol}=0.944mol

For the given chemical equation:

2H_2O\rightarrow 2H_2+O_2

By Stoichiometry of the reaction:

2 moles of water produces 1 mole of oxygen gas

So, 0.944 moles of water will produce = \frac{1}{2}\times 0.944=0.472moles of oxygen gas

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Moles of oxygen gas = 0.472 moles

Putting values in equation 1, we get:

0.472mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.472mol\times 32g/mol)=15.104g

To calculate the percentage yield of oxygen gas, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of oxygen gas = 10.2 g

Theoretical yield of oxygen gas = 15.104 g

Putting values in above equation, we get:

\%\text{ yield of oxygen gas}=\frac{10.2g}{15.104g}\times 100\\\\\% \text{yield of oxygen gas}=67.53\%

Hence, the percent yield of oxygen gas is 67.53 %.

7 0
4 years ago
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