a) 32 kg m/s
Assuming the spring is initially at rest, the total momentum of the system before the collision is given only by the momentum of the bowling ball:
The ball bounces off at the same speed had before, but the new velocity has a negative sign (since the direction is opposite to the initial direction). So, the new momentum of the ball is:
The final momentum after the collision is the sum of the momenta of the ball and off the spring:
where is the momentum of the spring. For the conservation of momentum,
b) -32 kg m/s
The change in momentum of bowling ball is given by the difference between its final momentum and initial momentum:
c) 64 N
The change in momentum is equal to the product between the average force and the time of the interaction:
Since we know , we can find the magnitude of the force:
The negative sign simply means that the direction of the force is opposite to the initial direction of the ball.
d) The force calculated in the previous step (64 N) is larger than the force of 32 N.
Answer:
58.44 C
Explanation:
Electric field is found by
Therefore, the charge is
Therefore, required charge is 58.44 C
Well, I guess you can come close, but you can't tell exactly.
It must be presumed that the seagull was flying through the air
when it "let fly" so to speak, so the jettisoned load of ballast
of which the bird unburdened itself had some initial horizontal
velocity.
That impact velocity of 98.5 m/s is actually the resultant of
the horizontal component ... unchanged since the package
was dispatched ... and the vertical component, which grew
all the way down in accordance with the behavior of gravity.
98.5 m/s = √ [ (horizontal component)² + (vertical component)² ].
The vertical component is easy; that's (9.8 m/s²) x (drop time).
Since we're looking for the altitude of launch, we can use the
formula for 'free-fall distance' as a function of acceleration and
time:
Height = (1/2) (acceleration) (time²) .
If the impact velocity were comprised solely of its vertical
component, then the solution to the problem would be a
piece-o-cake.
Time = (98.5 m/s) / (9.81 m/s²) = 10.04 seconds
whence
Height = (1/2) (9.81) (10.04)²
= (4.905 m/s²) x (100.8 sec²) = 494.43 meters.
As noted, this solution applies only if the gull were hovering with
no horizontal velocity, taking careful aim, and with malice in its
primitive brain, launching a remote attack on the rich American.
If the gull was flying at the time ... a reasonable assumption ... then
some part of the impact velocity was a horizontal component. That
implies that the vertical component is something less than 98.5 m/s,
and that the attack was launched from an altitude less than 494 m.
Answer:
t = 8.33 minutes
Explanation:
given,
Speed of Light, v = 3 x 10⁸ m/s
distance between sun to Earth = 1.5 x 10¹¹ m
time taken to reach earth = ?
we know,
Distance = speed x time
t = 500 s
1 min = 60 s
now,
t = 8.33 minutes
time taken by the light to reach earth is equal to 8.33 minutes.
Answer:a=v-u/t
=23-8/3
=5m/s hope you got your answer
Explanation: