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1 year ago

The ________ explains how our solar system probably formed from a giant cloud of gases and dispersed solid particles.

1 answer:

4 0

The nebular hypothesis explains how our solar system probably formed from a giant cloud of gases and dispersed solid particles.

<h3>What is Nebular hypothesis?</h3>

The most widely accepted theory in cosmogony to explain how the solar system formed and evolved is the nebular hypothesis. It implies that gas and dust orbiting the sun are what created the solar system.

Following are the steps in nebular theory:

As part of the cloud of gas and dust condenses into a core and becomes a protostar, the nebula changes into a solar nebula.

The material condensing might have been brought on by a nearby supernova shockwave.

An accretion disk is formed as the protostar's surrounding material disintegrates.

<h3>How did the solar system form, according to the nebular hypothesis?</h3>

The nebular hypothesis states that enormous clouds of hydrogen and helium imploded. The cloud's center heated up significantly after collapsing. The system then started to rotate as it became hotter and more compressed. The formation of the solar system started at this point.

Learn more about solar system here:

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A block attached to a spring with an unknown spring constant oscillates with a period of 2.0 s. What is the period if

Zigmanuir [339]

Answer:

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

Explanation:

The statement is incomplete. We proceed to present the complete statement: <em>A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if </em><em>a. </em><em>The mass is doubled? </em><em>b.</em><em> The mass is halved? </em><em>c.</em><em> The amplitude is doubled? </em><em>d.</em><em> The spring constant is doubled? </em>

We have a block-spring system, whose angular frequency ( $\omega$ ) is defined by the following formula:

$\omega = \sqrt{\frac{k}{m} }$ (1)

Where:

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass, measured in kilograms.

And the period ( $T$ ), measured in seconds, is determined by the following expression:

$T = \frac{2\pi}{\omega}$ (2)

By applying (1) in (2), we get the following formula:

$T = 2\pi\cdot \sqrt{\frac{m}{k} }$

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

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