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Anettt [7]
4 years ago
9

Call 7744882898 ::::::

Physics
1 answer:
Nostrana [21]4 years ago
8 0

Answer:

what does that mean?

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How do you give an example for finding net force?
Crazy boy [7]
--  6 people all trying to push a car out of snow

--  a Tug-o-War with 30 people of different sizes pulling on each end of the rope

--  you and your sister both pulling on the same doll (or Transformer)

--  lifting a book up from the table to a high shelf
    taking a book down from a high shelf to the table
    (one force is you; another force is gravity)

--  grabbing your big dog by his collar and trying to bring him inside

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7 0
3 years ago
On a floor directly underneath a second-floor balcony, there are several spherical drops of blood about 7 mm in diameter. Which
IrinaK [193]
The correct answer for this question is this one: "The drops dripped from a bloody knife about 2 ft above the ground."
<span>On a floor directly underneath a second-floor balcony, there are several spherical drops of blood about 7 mm in diameter. The statement that best accounts for the drops is that <em>the </em></span><span><em>drops dripped from a bloody knife about 2 ft above the ground.</em>
</span>
Hope this helps answer your question and have a nice day ahead.
7 0
3 years ago
1. What is evaporation and how does it affect weather?
alina1380 [7]

Answer:

Explanation:don’t know

8 0
3 years ago
What element is formed in the following nuclear reaction
MissTica

Answer:

Oxygen or more precisely, the O-15 isotope.

4 0
3 years ago
A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc
guajiro [1.7K]

Answer:

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

Explanation:

Expression for rate law for first order kinetics is given by:

a_o=a\times e^{-kt}

where,

k = rate constant  

t = age of sample

a_o = let initial amount of the reactant  

a = amount left after decay process  

We have :

a_o=x

a=58\%\times x=0.58x

t = 95 s

0.58x=x\times e^{-k\times 95 s}

\k= 0.005734 s^{-1}

Half life is given by for first order kinetics::

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{0.005734 s^{-1}}=120.86 s

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

3 0
3 years ago
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