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grandymaker [24]
2 years ago
12

A student found the mass of an object to be 5.5 g. The actual mass of the object is 5.3 g. What is the percent error in the meas

urement?
Chemistry
2 answers:
Salsk061 [2.6K]2 years ago
8 0

Answer: 3.6%

5.5 - 5.3 and divide it by 5.5. Then multiply this by 100

Explanation:

This will get you 3.6%

Orlov [11]2 years ago
3 0

Answer:

3.8%

Explanation:

For future students i took the test and this is correct. I found out the hard way so take my word :)

hope i helped

-lvr

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UkoKoshka [18]
X moles of hot water vapor(H2O) * 1 mol Fe3O4 / 4 mol H2O * 233.55g Fe3O4 / 1 mol = 275 g

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3 years ago
Put the list in chronological order (1–5).
Leokris [45]

Explanation:

Filtration is a separation technique in which solid particles suspended in liquid medium are separated by allowing the mixture through the pores of the filter paper. By this solid particles get collect on filter paper and liquid drains out from the pores of the filter paper.

The chronological order for given steps will be:

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4 0
3 years ago
Read 2 more answers
Suppose you needed a 0.0250 M sodium thiosulfate solution to conduct 6 titrations. Explain how you would make up this solution u
AysviL [449]

Explanation:

According to the law of dilution,

       M_{1}V_{1} = M_{2}V_{2}

The given data is as follows.

   M_{1} = 0.4782,     V_{1} = ?

    M_{2} = 0.025 ,    V_{2} = 250 mL

Hence, we will calculate the value of V_{1} as follows.

              V_{1} = \frac{M_{2} \times V_{2}}{M_{1}}

                          = \frac{0.025 \times 250}{0.4782}

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4 0
3 years ago
an iron bar weighed 664 g. after the bar had been standing in moist air for a month, exactly one-eighth of the iron turned to ru
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The final mass of the iron bar and the rust when the weight of the bar was 664g and the bar had been standing in moist air for a month, will be 688.456g.

One-eighth of the iron bar turns to rust, which means the mass of the iron bar that has undergone rusting= 664/8= 83g

Thus, the mass of pure iron left after rusting has taken place will be= (664-83)g= 581g.

The equation of rusting is as follows

4Fe + 3O2 + 6H2O → 4Fe(OH)3

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Therefore, mass of iron bar= (581+ 107.456)g

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5 0
2 years ago
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Answer:

9 orbits, The 3d subshell will be having 5 orbitals. On adding all the orbitals of 3s, 3p and 3d we get a total of 9 orbitals. Therefore, there are 9 orbitals in the third shell.

6 0
2 years ago
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