More than ½ of the world's forests have been lost to deforestation. True False

Chemistry

2 answers:

RideAnS [48]3 years ago

8 0

The answer is false

cestrela7 [59]3 years ago

5 0

According to the World Resources Institute, more than 80 percent of the Earth's natural forests already have been destroyed

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What is the main reason that it takes 2 to 3 minutes for the reaction to occur between sucrose and sulfuric acid in the dehydrat

soldier1979 [14.2K]

There is a time delay of almost two to three minutes before the reaction proceeds because of the following processes:

1) The acid starts to go yellow as the dehydration begins.

2) The rate of dehydration then accelerates as the acid heats up because the reaction is exothermic/chemical (releases energy by light or heat). As the sugar molecules are stripped of water, the heat generated turns the water into steam which then expands the remaining carbon into a porous, smoking, black column.

3) This expands out of the reaction vessel, producing a choking acrid vapor and the smell of burned sugar.

At this stage, sulfuric acid is highly corrosive and will burn skin so one must avoid contact with it.

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BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w

Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

Explanation:

Given: The base dissociation constant: $K_{b}$ = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: $K_{w}$ = 1 × 10⁻¹⁴

The acid dissociation constant ( $K_{a}$ ) for the weak acid (BH⁺) can be calculated by the equation:

$K_{a}. K_{b} = K_{w}$

$\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}$

$\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}$

Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:

Reaction involved: BH⁺ + H₂O ⇌ B + H₃O+

Initial: 0.1 M x x

Change: -x +x +x

Equilibrium: 0.1 - x x x

The acid dissociation constant: $K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}$