Answer:
E. Water Freezing
Explanation:
Entropy refers to the degree of disorderliness of a system.
A. Water Evaporating: There is an increase in entropy, this is because the phase change is from liquid to gas. Gas particles are more disordered than liquid.
B. Dry Ice sublimating: Sublimating refers to a phase change from solid to gas. This is an increase in entropy, this is because the gas particles are more disordered than solid particles
C. Water Boiling: The phase change is from liquid to gaseous state. There is an increase in entropy. Gas particles are more disordered than liquid.
D. Ice melting: The phase change is from solid to liquid state. There is an increase in entropy. Liquid particles are more disordered than that of solid.
E. Water Freezing: The phase change is from liquid to solid state. There is a decrease in entropy. solid particles are less disordered than those of liquid.
<span>Electronegativity is the property of an element that measures the
ability of it to attract and form electron bonds. The trend in the periodic
table in terms of electronegativity decreases from right to left and from top
to bottom. In the case of period 4, the element with the highest electronegativity
is bromine. </span>
Answer:
Alpha Particle, Beta Particles and Gamma Rays
Explanation:
Answer:
The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is
.
Explanation:
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of gas = 104 kPa
= final pressure of gas = 52 kPa
= initial volume of gas = ![2.0m^3](https://tex.z-dn.net/?f=2.0m%5E3)
= final volume of gas = ?
= initial temperature of gas = ![21.1^oC=273+21.1=294.1K](https://tex.z-dn.net/?f=21.1%5EoC%3D273%2B21.1%3D294.1K)
= final temperature of gas = ![-5.0^oC=273+(-5.0)=268 K](https://tex.z-dn.net/?f=-5.0%5EoC%3D273%2B%28-5.0%29%3D268%20K)
Now put all the given values in the above equation, we get:
![\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}](https://tex.z-dn.net/?f=%5Cfrac%7B104%20kPa%5Ctimes%202.0m%5E3%7D%7B294.1%20K%7D%3D%5Cfrac%7B52%20kPa%5Ctimes%20V_2%7D%7B268%20K%7D)
![V_2=3.64 m^3](https://tex.z-dn.net/?f=V_2%3D3.64%20m%5E3)
The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is
.
Answer:The answer is D.1,3
Explanation: