Answer:
the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
The computation of the initial concentration of the SCN^- in the mixture is as follows:
As we know that
As it is mentioned in the question that KSCN is present 10 mL of 0.05 M
So, the total milimoles of SCN^- is
= 10 × 0.05
= 0.5 m moles
The total volume in mixture is
= 45 + 10 + 30
= 85 mL
Now the initial concentration of the SCN^- is
= 0.5 ÷ 85
= 0.00588 M
hence, the initial concentration of SCN- in the mixture is 0.00588 M
Answer:
Im not smart either but im pretty sure its D because its a pie chart so its asking how many and pie charts tell you how much something has
Explanation:
Michigan v. Tyler was the Supreme court ruling that they violated when
warrantless search was done.
<h3>Michigan v. Tyler case</h3>
The Court of Appeals of the State of Michigan affirmed the conviction for the
exception of a warrantless search only in the case of an arson.
In this case, there was no arson involved which is against the rule of law as
various items (stolen money, illegal weapons, drugs) were only searched for.
This thereby violates the U.S. Supreme Court ruling between Michigan v.
Tyler.
Read more about Michigan v. Tyler case here brainly.com/question/1622038
Answer:
0.1357 M
Explanation:
(a) The balanced reaction is shown below as:
(b) Moles of 
can be calculated as:
Or,
Given :
For :
Molarity = 0.1450 M
Volume = 10.00 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 10×10⁻³ L
Thus, moles of :
Moles of = 0.00145 moles
From the reaction,
1 mole of react with 2 moles of NaOH
0.00145 mole of react with 2*0.00145 mole of NaOH
Moles of NaOH = 0.0029 moles
Volume = 21.37 mL = 21.37×10⁻³ L
Molarity = Moles / Volume = 0.0029 / 21.37×10⁻³ M = 0.1357 M
