Answer:
Approximately
, assuming that
.
Explanation:
Let
denote the time required for the package to reach the ground. Let
and
denote the initial and final height of this package.
.
For this package:
- Initial height:
. - Final height:
(the package would be on the ground.)
Solve for
, the time required for the package to reach the ground after being released.
.
.
Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at
.) From calculations above, the package would travel forward at that speed for about
. That corresponds to approximately:
.
Hence, the package would land approximately
in front of where the plane released the package.
Answer:
The velocity of the stone is 2.57 m/s.
Explanation:
Given that
Height = 0.337 m
We need to calculate the velocity of the stone
Using equation of motion

Where, v = velocity of stone
u = initial velocity
g = acceleration due to gravity
h = height
Put the value into the formula



Hence, The velocity of the stone is 2.57 m/s.
Answer:
We use X-rays to help the injured, Radiowaves to communicate or entertain, and Visible light to see.