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3 years ago

Sodium is more reactive than magnesium. Give reason

Chemistry

2 answers:

scoray [572]3 years ago

4 0

Answer:

The alkaline-earth metals tend to lose two electrons to form M 2+ ions (Be2+, Mg2+, Ca2+, and so on). These metals are less reactive than the neighboring alkali metal. Magnesium is less active than sodium; calcium is less active than potassium; and so on. These metals become more active as we go down the column.

Morgarella [4.7K]3 years ago

3 0

Answer: According to the reactivity of metals Sodium is the second metal while Magneesium is the fourth metal. The metal in the top of the reactivity serise table are more reactive.

(The series obtained by the arrangement of metals in the decending oder of their reactivity is the REACTIVITY SERIES TABLE)

Explanation:

Na

Mg

Therefore Sodium is more reactive than Magnesium

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When does diversity within a speices occur

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A. Over many generations

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4 years ago

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) If you have 4 moles of zinc and 4 moles of hydrochloric acid, which of these would be the l

Y_Kistochka [10]

Answer:

D) hydrochloric acid.

Explanation:

The balanced equation for the mentioned reaction is:

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g),

It is clear that 1.0 moles of Zn react with 2.0 moles of HCl to produce 1.0 moles of ZnCl₂ and 1.0 mole of H₂.

From stichiometry; Zn reacts with HCl with (1: 2) molar ratio.

∴ 2.0 mol of Zn (the remaining 2.0 mol is in excess) react completely with 4.0 mol of HCl with (1: 2) molar ratio.

So,

the limiting reactant is HCl and the excess reactant is Zn.

Thus, the right choice is: D) hydrochloric acid.

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4 years ago

Which is the best description of a molecule?

Romashka-Z-Leto [24]

A molecule of a compound is composed of at least two types of atoms.

Explanation:

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3 years ago

Read 2 more answers

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti

ella [17]

Answer :

The mass of excess mass of $Na_2CO_3$ , $AgNO_3,Ag_2CO_3\text{ and }NaNO_3$ are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.

Explanation : Given,

Mass of $Na_2CO_3$ = 4.25 g

Mass of $AgNO_3$ = 7.50 g

Molar mass of $Na_2CO_3$ = 106 g/mole

Molar mass of $AgNO_3$ = 170 g/mole

Molar mass of $Ag_2CO_3$ = 276 g/mole

Molar mass of $NaNO_3$ = 85 g/mole

First we have to calculate the moles of $Na_2CO_3$ and $AgNO_3$ .

$\text{Moles of }Na_2CO_3=\frac{\text{Mass of }Na_2CO_3}{\text{Molar mass of }Na_2CO_3}=\frac{4.25g}{106g/mole}=0.040moles$

$\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{7.50g}{170g/mole}=0.044moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Na_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2NaNO_3$

From the balanced reaction we conclude that

As, 2 moles of $AgNO_3$ react with 1 mole of $Na_2CO_3$

So, 0.044 moles of $AgNO_3$ react with $\frac{0.044}{2}=0.022$ moles of $Na_2CO_3$

From this we conclude that, $Na_2CO_3$ is an excess reagent because the given moles are greater than the required moles and $AgNO_3$ is a limiting reagent and it limits the formation of product.

The excess mole of $Na_2CO_3$ = 0.040 - 0.022 = 0.018 mole

Now we have to calculate the mass of excess mole of $Na_2CO_3$ .

$\text{Mass of }Na_2CO_3=\text{Moles of }Na_2CO_3\times \text{Molar mass of }Na_2CO_3=(0.018mole)\times (106g/mole)=1.908g$